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Romashka [77]
3 years ago
9

Lee is selling spirit wear for a

Mathematics
2 answers:
rewona [7]3 years ago
8 0

Answer:

Lee sold 16 hats

Step-by-step explanation:

16*8=128

12*12=144

128

+ 144

$272

elena-14-01-66 [18.8K]3 years ago
6 0
I agree with the other comment!!
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Write an expression to find the perimeter of the trapezoid: y+3, y, y+4, y+ 2
timofeeve [1]
(y+3)+y+(y+4)+(y+2)
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Simplify (3/4ab^7)^3
stira [4]

Answer:

33a3b21  

 ———————

   26  

Step-by-step explanation:


3 0
3 years ago
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Find the approximate volume of the figure below, composed of a cone, a cylinder, and a hemisphere. If necessary, round your answ
mixas84 [53]

Answer:

Volume of the solid = 480.42m³

Step-by-step explanation:

To sov this question, we'll have to break the solid into different shapes of solid to solve it easily.

Volume of a cylinder = πr²h

volume of a hemisphere = 4/3πr³

Volume of a cone = ⅓πr²h

π = 3.14

r = 3m

h(cylinder) = 11m

Slant height of cone = 3√(2)

Height of cone = ?

To find height of cone, we can use pythagorean theorem

a² = b² + c²

[ 3√(2)]² = 3² + c²

9*2 = 9 + c²

C² = 18 - 9

C = 9m

Height of the cone = 9m

Volume of a cylinder = πr²h

V = 3.14 * 3² * 11

V = 310.86m³

Volume of the cylnder = 310.86m³

Volume of the hemisphere = 4/3πr³

V = 3.14 * 3³

V = 84.78m³

Volume of the hemisphere = 84.78m³

Volume of the cone = ⅓πr²h

V = ⅓ * 3.14 * 3² * 9

V = 84.78

Volume of the cone = 84.78m³

Volume of the solid = volume of cone + volume of hemisphere + volume of cylinder

Volume of the solid = 84.78 + 84.78 + 310.86

Volume = 480.42m³

5 0
3 years ago
Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)
Crazy boy [7]

Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

1\text{ m}^2=10.7639\text{ ft}^2

1\text{ sec}=\frac{1}{3600}\text{ hour}

1\text{ cal}=0.003968\text{ BTU}

Converting temperature unit,

^\circ C\times \frac{9}{5}+32=^\circ F

1^\circ C\times \frac{9}{5}+32=33.8^\circ F

So, 1^\circ C=33.8^\circ F

Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

3 0
3 years ago
I need help with these because recently we have been learning this and I don't get any of this.
Aleksandr-060686 [28]
It is upside down, can't see it properly!
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