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Scilla [17]
3 years ago
14

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Mathematics
1 answer:
Crazy boy [7]3 years ago
3 0

Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

1\text{ m}^2=10.7639\text{ ft}^2

1\text{ sec}=\frac{1}{3600}\text{ hour}

1\text{ cal}=0.003968\text{ BTU}

Converting temperature unit,

^\circ C\times \frac{9}{5}+32=^\circ F

1^\circ C\times \frac{9}{5}+32=33.8^\circ F

So, 1^\circ C=33.8^\circ F

Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

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The average rate of change of g(x) between x = 4 and x = 7 is 5/6 . Which statement must be true?
Blizzard [7]

Answer:

\frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}  would be the correct statement.

Step-by-step explanation:

As we know that

Average rate of change = Change in output / Change in input    

                                        =  Δy  / Δx

                                        =\frac{y_{2} -y_{1}}{x_{2} -x_{1}}

                                        =\frac{g(x_{2})-g(x_{1})}{x_{2}-x_{1}}

                                         =\frac{g(7)-g(4)}{7-4}                    

As the average rate of change of g(x) between x = 4 and x = 7 is 5/6.

so

\:Average\:rate\:of\:change\:=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}

                                  \frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}

Therefore, \frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}  would be the correct statement.                      

6 0
3 years ago
Find the center and foci of the ellipse (x+5)/5+(y+9)/9=1
Katena32 [7]

(x+5)/5+(y+9)/9=1


The center is (-5,-9)

c^2 = 9-5 =4

c=2

foci =2

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Answer:

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