The answer is
round cake - 82.42 in²
rectangular cake - 114 in²
Round cake:
d = 7 in
r = d/2 = 7 in / 2 = 3.5 in
h = 2 in
The surface are of a cylinder is:
A = 2πr² + 2πrh
The surface are of the round cake (which is actually a cylindrical cake) excluding the bottom is:
A = 2πr² + 2πrh - πr²
A = πr² + 2πrh
A = 3.14 * 3.5² + 2 * 3.14 * 3.5 * 2
= 38.46 + 43.96
= 82.42 in²
Rectangular cake:
w = 6 in
l = 9 in
h = 2 in
The surface are of a rectangle is:
A = 2wl + 2wh + 2lh
The surface are of the rectangular cake excluding the bottom is:
A = 2wl + 2wh + 2lh - wl
A = wl + 2wh + 2lh
A = 6 * 9 + 2 * 6 * 2 + 2 * 9 * 2
= 54 + 24 + 36
= 114 in²
Step-by-step explanation: This answer is not mine but JcAlmighty’s so all credits go to them.
Answer:
i think it is -14.56
Step-by-step explanation:
Answer:
234.85
Step-by-step explanation:
This was easy!!!
(The gardener comes 4 times a month... so divide 85.40 by 4 and you will get 21.35. Each time he comes, he gets 21.35 and by the end of the month, he has 85.40. It says he already came 11 times. So 4 + 4 = 8 + another 4 that equals 12. He came only two months and a few weeks. This means multiply 85.40 by 2 so you would get 170.8. It said he came 11 times so substract 11 from 8 and you would get 3. So multiply 21.35 by 3 and get a total of 64.05. Add 170.8 and 64.05 to get 234.85!!! The answer is 234.85 or C!!!!
Answer:
30
Step-by-step explanation:
fish cant drown
9514 1404 393
Answer:
a. 1.48 seconds
Step-by-step explanation:
You want to find the larger value of t such that h(t) = 10.
-16t^2 +25t +8 = 10
16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form
Using the quadratic formula, we find the values of t to be ...
t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32
t ≈ 0.08 or 1.48
The ball goes in the hoop about 1.48 seconds after it is thrown.
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<em>Additional comment</em>
The quadratic formula tells us the solution to ...
ax² +bx +c = 0
is given by ...
Here, we have a=16, b=-25, c=2. Of course, our variable is t, not x, but the relation is the same.