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3 years ago

Which expression calculates the time in hours an object takes to travel 38 miles at a speed of 2 m/h ? (I NEED HELP ASAP)

Mathematics

1 answer:

defon3 years ago

4 0

Answer:

Option B : 38/2 is the correct answer.

Step-by-step explanation:

Given that:

Distance to travel = 38 miles

Speed of object = 2 miles per hour

Distance = Speed * Time

To find the time, we will divide the distance by speed.

Time = $\frac{Distance}{Speed}$

Putting values of distance and speed in the formula.

Time = 38/2

Hence,

Option B : 38/2 is the correct answer.

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I need the complete answer to this problem, please circle the final answer and what I should write

goblinko [34]

Answer:

$f(t) = 8400(1.0018)^{12t}$

2.22%

Step-by-step explanation:

$8400 is invested in an account earning 2.2% interest (APR), compounded monthly.

So, the value of the account after t years will be given by

$f(t) = 8400 (1 + \frac{2.2}{12 \times 100} )^{12t} = 8400(1.0018)^{12t}$ {Rounded to the four decimal places} (Answer)

Now, for t = 1 year, f(1) = $8586.67

So, the percentage of growth per year (APY) = $\frac{(8586.67 - 8400) \times 100}{8400} = 2.22$ % {Rounded to the nearest hundredth of percent} (Answer)

5 0

3 years ago

In a championship basketball game, Paula Zimmerman scored twice as many points as Maria Kaminsky. If the total number of points

Strike441 [17]

Answer:

x=34

y=17

Step-by-step explanation:

Let Paula's score be= x

Let Maria's score be=y

Given:

x=2y

x+y=51

Substitution:

2y+y=51

Formula:

2y+y=51

3y=51

y=17

x=2y

x=2(17)

x=34

Proof:

x+y=51

34+17=51

51=51

Hope this helps ;) ❤❤❤

5 0

3 years ago

Planes have edges true or false

Cerrena [4.2K]

False planes do not have edges.

6 0

3 years ago

Kristin spent $131 on shirts. Fancy shirts cost $28 and plain shirts cost $15. If she bought a total of 7 shirts then how many o

KIM [24]

Answer:

Kristin bought 5 plain shirts and 2 fancy shirts.

Hope this helps!

4 0

3 years ago

How to differentiate ?

Bas_tet [7]

Use the power, product, and chain rules:

$y = x^2 (3x-1)^3$

• product rule

$\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}$

• power rule for the first term, and power/chain rules for the second term:

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}$

• power rule

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3$

Now simplify.

$\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}$

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

$\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) = \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)$

Differentiate both sides and you end up with the same derivative:

$\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2$

7 0

2 years ago