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3 years ago

10

Enter the unknown value that makes this statement true. 25% of is 35

1 answer:

Eva8 [605]3 years ago

4 0

Answer:

25% of 140 is 35

Step-by-step explanation:

If 35 is 25% then we can multiply it by 4 to get 100%.

35 x 4=140

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A light bulb consumes 1440 watt-hours per day. How many watt-hours does it consume in 4 days and 18 hours.

dimaraw [331]

Answer:

6840

Step-by-step explanation:

Well we know there's 24 hours in a day so dividing that by 1440 we get 60. Now we know that it consumes 60 watts ever hour. so now we just have to figure out how many hours there are and times that by 60. So there are 96 hours in 4 days plus 28=114. So times that by 60 ( watts) 114×60=6840

So that's your awnser.

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6 0

3 years ago

How to solve this problem?

cluponka [151]

have you tried 42 because it's a 90 degree triangle and 30+18+42 equals 90

7 0

3 years ago

What are points 7,11,12,and 5

klasskru [66]

12 = 60 degrees.

The "C" pattern means that whatever is on the top/bottom corner will be equal to the opposite one.

4 0

3 years ago

A shop is having a sale all items are reduced work out the sale price of an item normally priced at £60

Naddik [55]

Question:

A shop is having a sales all items are reduced by 25%. Work out the sale price of an item normally priced at £60?

Answer:

The new price is £45

Step-by-step explanation:

Given

$Sales\ price = \pounds 60$

$Rate = 25\%$

First, calculate the reduction

$Reduction = Rate * Sales\ price$

$Reduction = 25\% * \pounds 60$

$Reduction = \pounds 15$

The new price is:

$New = Sales\ price - Reduction$

$New = \pounds 60 - \pounds 15$

$New = \pounds 45$

3 0

3 years ago

WILL GIVE BRAINLIEST Chang deposited $5000 into an account with a 4.8% annual interest rate, compounded monthly. Assuming that n

Mariulka [41]

Answer:

9.42 years (= 113 months)

Step-by-step explanation:

Use the compound rate interest formula:

$A=P(1+\frac{r}{n})^{nt}$

where:

A = amount
P = principal
r = interest rate (in decimal format)
n = number of times interest is compounded per unit t
t = time

Given:

A = $7850
P = $5000
r = 4.8% = 0.048
n = 12
t = years

$\implies 7850=5000(1+\frac{0.048}{12})^{12t}$

$\implies 7850=5000(1.004)^{12t}$

$\implies \dfrac{7850}{5000}=(1.004)^{12t}$

$\implies 1.57=(1.004)^{12t}$

Take natural logs:

$\implies \ln1.57=\ln(1.004)^{12t}$

$\implies \ln1.57=12t\ln(1.004)$

$\implies t=\dfrac{\ln 1.57}{12 \ln1.004}$

$\implies t=9.42\textsf{ years (nearest hundredth)}$

$\implies t=113 \textsf{ months}$

5 0

2 years ago