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pishuonlain [190]
3 years ago
9

Given right triangle ABC. To the nearest degree, find the measure of angle B.

Mathematics
1 answer:
DedPeter [7]3 years ago
4 0

Answer:

Step-by-step explanation:

We have the length of AC which is opposite angle B; we also have the length of the hypotenuse.  We will use trig here to solve for angle B.  The sin ratio is the one that fits.

sin(B) = side opposite / hypotenuse:

sin(B)= \frac{ 4.8}{ 5.1} so

sin(B) = .9411764706

Now we will use the 2nd button on our calculators.  This will give us the missing angle value.  Press 2nd then sin and you will see on your screen:

sin^{-1 (

Enter that decimal after the open parenthesis and hit "enter" to get

B = 70.25 or 70°

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What is the variable y in w= x y/z?
AleksAgata [21]
Multiply by z to get
wz = xy
divide by x
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3 years ago
Is line 1 (1,5) (3,-2) and like 2 (-3,2) (4,0) perpendicular of parallel?
Lera25 [3.4K]
  • Slope Formula: \frac{y_2-y_1}{x_2-x_1}

So remember that <u>perpendicular lines have slopes that are negative reciprocals to each other</u> and <u>parallel lines have the same slope.</u> To find out if they are either parallel or perpendicular, plug the pair of points into the slope formula to find their slopes:

\textsf{Line 1}\\\\\frac{5-(-2)}{1-3}=-\frac{7}{2}\\\\\textsf{Line 2}\\\\\frac{0-2}{4-(-3)}=-\frac{2}{7}

Since these slopes aren't the same nor are they negative reciprocals to each other, <u>the lines are neither parallel nor perpendicular.</u>

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3 years ago
Question Help Of 515515 samples of seafood purchased from various kinds of food stores in different regions of a country and gen
Setler79 [48]

Answer:

(0.5848 ; 0.6552)

We are confident that about 58% to 66% of sea foods in the country are Mislabelled.

No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

Step-by-step explanation:

Sample size, n = 51

p = 0.62

1 - p = 1 - 0.62 = 0.38

n = 515

Confidence level = 90% = Zcritical at 90% = 1.645

Confidence interval = (p ± margin of error)

Margin of Error = Zcritical * sqrt[(p(1-p))/n]

Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]

Margin of Error = 1.645 * 0.0214

Margin of Error = 0.035203

Lower boundary = (0.62 - 0.035203) = 0.584797

Upper boundary = (0.62 + 0.035203) = 0.655203

(0.5848 ; 0.6552)

We are confident that about 58% to 66% of sea foods in the country are Mislabelled.

No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

3 0
3 years ago
The pesticide diazinon is in common use to treat infestations of the German cockroach, Blattella germanica. A study investigated
cluponka [151]

Answer:

We conclude that there is no difference in the proportion of cockroaches that died on each surface.

Step-by-step explanation:

We are given that a study investigated the persistence of this pesticide on various types of surfaces.

After 14 days, they randomly assigned 72 cockroaches to two groups of 36, placed one group on each surface, and recorded the number that died within 48 hours. On the glass, 18 cockroaches died, while on plasterboard, 25 died.

<em>Let </em>p_1<em> = proportion of cockroaches that died on glass surface.</em>

<em />p_2<em> = proportion of cockroaches that died on plasterboard surface.</em>

So, Null Hypothesis, H_0 : p_1-p_2 = 0      {means that there is no difference in the proportion of cockroaches that died on each surface}

Alternate Hypothesis, H_A : p_1-p_2\neq 0      {means that there is a significant difference in the proportion of cockroaches that died on each surface}

The test statistics that would be used here <u>Two-sample z proportion</u> <u>statistics</u>;

                       T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}  } }  ~ N(0,1)

where, \hat p_1 = sample proportion of cockroaches that died on glass surface = \frac{18}{36} = 0.50

\hat p_2 = sample proportion of cockroaches that died on plasterboard surface = \frac{25}{36} = 0.694

n_1 = sample of cockroaches on glass surface = 36

n_2 = sample of cockroaches on plasterboard surface = 36

So, <u><em>test statistics</em></u>  =  \frac{(0.50-0.694)-(0)}{\sqrt{\frac{0.50(1-0.50)}{36}+\frac{0.694(1-0.694)}{36}  } }

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The value of z test statistics is -1.712.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no difference in the proportion of cockroaches that died on each surface.

8 0
3 years ago
In a two digit number, the tens digit is 2 less than the units digit multiplied by three. The reversed number is half the origin
Papessa [141]

Answer:

73

Step-by-step explanation:

Original number: XY

x = 3y - 2

10y + x = (10x + y) / 2 + 1/2

substitution: 10y + 3y - 2 = 13y - 2 = (10 * (3y - 2) + y) / 2 + 1/2

* 2 both sides and simplify: 26y - 4 = 31y - 19

31y - 26y = -4 + 19

5y = 15

y = 3

x = 7

Original number: 73

8 0
2 years ago
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