A ball is thrown from an initial height of 6 feet with an initial upward velocity of 17 ft/s. The ball's height h (in feet) afte
r t seconds is given by the following.
h=6+17t-16t^2
Find all values of t for which the ball's height is 10 feet.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
t=___seconds
1 answer:
Answer:
32
Explanation:
6 + 29t - 16t^2 = 18. 16t^2 - 29t + 12 = 0. t = (29 +- √(29^2 - 4*12*16))/32.
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