A ball is thrown from an initial height of 6 feet with an initial upward velocity of 17 ft/s. The ball's height h (in feet) afte
r t seconds is given by the following.
h=6+17t-16t^2
Find all values of t for which the ball's height is 10 feet.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
t=___seconds
1 answer:
Answer:
32
Explanation:
6 + 29t - 16t^2 = 18. 16t^2 - 29t + 12 = 0. t = (29 +- √(29^2 - 4*12*16))/32.
You might be interested in
Answer:
first picture d
second d
third a
forth a
5th c
im not that great at math tho
Step-by-step explanation:
Answer:
n=601
Step-by-step explanation:
Formula used:
Solution:
Where,
As there is no previous estimate for p
Then, p=0.5
Here on using the table
Also,
E=0.04
p=0.5
Thus,
n=600.2279407
On approximating the value,
n=601
Answer:
128
Step-by-step explanation:
-7x+2 = -18(-7)+2=126+2=128
Answer:
(2.19 x 4) + (0.79 x 3)
Step-by-step explanation:
ok so u hv to take 2.19 and multiply it by four. Then take 0.79 and multiply it by three.
No because 3*2= 6 while 5*2=10 so if it was equivalent it would of been 3/5 to 6/10