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2 years ago

Chalk contains 10% calcium 3% carbon and 12% oxygen find the amount in grams of each of these compounds in 1 kg of chalk

Mathematics

1 answer:

LUCKY_DIMON [66]2 years ago

6 0

Answer:

100 gm calcium, 30gm carbon and 120gm oxygen

Step-by-step explanation:

10% of a kg is 100gm of calcium, 3% of 1 kg is 30gm of carbon and 12% of a kg is 120gm of oxygen

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Plz i need this asap, if you do not know all of them, plz do not answer

Lelechka [254]

1. sqrt 52 = 7.211 rounds to 7

2. irrational number

3. sqrt 441 = 21....rational

4. 12^2 + 3^2 = h^2
144 + 9 = h^2
153 = h^2
sqrt 153 = h
12.4 = h <===

5. 6^2 + b^2 = 18^2
36 + b^2 = 324
b^2 = 324 - 36
b^2 = 288
b = sqrt 288
b = 16.97 rounds to 17 <==

6. 39^2 + 52^2 = c^2
1521 + 2704 = c^2
4225 = c^2
sqrt 4225 = c
65 = c
(39 + 52) - 65 = 91 - 65 = 26 miles shorter <==

7. 4^2 + b^2 = 16^2
16 + b^2 = 256
b^2 = 256 - 16
b^2 = 240
b = sqrt 240
b = 15.49 rounds to 15.5 <==

8. ?

8 0

3 years ago

11. The formula for the are of a triangle is A = 1/2 bh.

RoseWind [281]

Answer:

2A/b

Step-by-step explanation:

A=1/2(b)(h)

2A=(b)(h) Multiply both sides by 2

2A/b=h Divide both sides by b

h=2A/b

7 0

2 years ago

What decimal is equivalent to 1.25%

matrenka [14]

The answer is 0.0125

5 0

2 years ago

Read 2 more answers

Tony is driving from alma ,Michigan to Elizabeth city, North Carolina . The drive covers a total distance of 1,100 miles. Tony c

Natalka [10]

<span>3 tanks because he can do 400 miles on tank, and he's goin 1,100 miles, he does 400 miles with first tank, next tank he gets to 800 miles, and then he uses 3/4 of last tank to get to 1,100, he will then have 100 miles left on the tank though.</span>

4 0

2 years ago

A professor has recorded exam grades for 10 students in his class, but one of the grades is no longer readable. If the mean sco

Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

$\frac{R+x}{10} =80$

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

$\frac{R}{9} = 85\\$ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

$\frac{R}{9} = 85\\R=85*9= 765$

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

$\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35$

4 0

2 years ago