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pentagon [3]
2 years ago
12

CAN SOME ONE PLS HELP ME THIS IS REALLY HARD

Mathematics
2 answers:
Aleks [24]2 years ago
5 0

Car A can travel 275 miles and car B can travel 220 miles

Step-by-step explanation:

pls mark as brainliest

Dmitry_Shevchenko [17]2 years ago
4 0

Answer: 1.25 times as far

Step-by-step explanation:

This problem requires you to find something called the unit rate.

Getting the unit rate for Car A is very simple, and can be found to be 25mi/gal.

To find the unit rate for Car B, simply look at the second row.  Because the car can go 60 miles on 3 gallons of gas, divide both these numbers by 3 to get 20mi/gal.

Then, simply multiply both of these numbers by 11 to get 25 * 11 = 275, and 20 * 11 = 220.

Then, by doing 275/220, you get your answer: 1.25.

Hope it helps :) and let me know if you want me to elaborate.

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An aircraft emergency locator transmitter (ELT) is a device designed to transmit a signal in the case of a crash. The ACME Manuf
iren [92.7K]

Answer:

a) P(ACME) = 0.7

b) P(ACME/D) = 0.5976

Step-by-step explanation:

Taking into account that ACME manufacturing company makes 70% of the ELTs, if a locator is randomly selected from the general population, the probability that it was made by ACME manufacturing Company is 0.7. So:

P(ACME) = 0.7

Then, the probability P(ACME/D) that a randomly selected locator was made by ACME given that the locator is defective is calculated as:

P(ACME/D) = P(ACME∩D)/P(D)

Where the probability that a locator is defective is:

P(D) = P(ACME∩D) + P(B. BUNNY∩D) + P(W. E. COYOTE∩D)

So, the probability P(ACME∩D) that a locator was made by ACME and is defective is:

P(ACME∩D) = 0.7*0.035 = 0.0245

Because 0.035 is the rate of defects in ACME

At the same way, P(B. BUNNY∩D) and P(W. E. COYOTE∩D) are equal to:

P(B. BUNNY∩D) = 0.25*0.05 = 0.0125

P(W. E. COYOTE∩D) = 0.05*0.08 = 0.004

Finally, P(D) and P(ACME/D) is equal to:

P(D) = 0.0245 + 0.0125 + 0.004 = 0.041

P(ACME/D) = 0.0245/0.041 = 0.5976

5 0
3 years ago
A rectangle with a perimeter of 19m^2+2m-10 and a width of m^2 write an expression for the lenght
expeople1 [14]

Answer:

8.5m^{2}+ m -5

Step-by-step explanation:

Since perimeter, P=19m^{2}+ 2m -10 and we know that P=2(l+w) then P=2(l+m^{2})=2l+2m^{2}

The length will be 2l=19m^{2}+ 2m -10-2m^{2}=17m^{2}+ 2m -10

Now l=8.5m^{2}+ m -5

6 0
3 years ago
If (-2, y) lles on the graph of y = 3^x, then y =
sweet [91]
<h3>Answer:</h3>

\frac{1}{9}

<h3>Step-by-step explanation:</h3>

We know that x=-2, so substitute that into the equation. y=3^{-2}

With negative powers, instead of making the result negative, you divide one by it.  Mathematically speaking, x^{-y}=\frac{1}{x^y}.  This makes our equation: y=\frac{1}{3^2}

Finally, simplify the exponent. y=\frac{1}{9}

8 0
3 years ago
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Four different roads from Town A to Town B, and three different roads run from Town B to Town C. Two roads also run from Town A
LekaFEV [45]

Answer:

196

Step-by-step explanation:

To solve this, I broke it down into two parts.

A. Number of routes going to Town C

4 x 3 + 2 = 14

B. Number of routes going back to Town A

3 x 4 + 2 = 14

From here, it is easy to see what to do. Since there are 14 routes going to Town C and 14 routes going back, the answer is 14 x 14 = 196.

5 0
3 years ago
GEOMETRY. 10 points :)
Lunna [17]
I think it's true. I'm so sorry if it's wrong
6 0
3 years ago
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