Is the following exponential graph increasing or decreasing? If it is, what exponent problem is it? Explain.

On Naomi's cell phone plan, the amount she pays each month for international text messages is proportional to the number of inte

egoroff_w [7]

A. Constant of proportionality in this proportional relationship is; k=5

B. Equation to represent this proportional relationship is : c=t/k

Step-by-step explanation:

A.Given that : the amount she pays each month for international text messages is proportional to the number of international texts she sends, then

$3.20 k = 16 ---------where k is the constant of proportionality

k= 16/3.20 =5

k=5

B. Let c be the cost of sending the texts per month and t be the number of texts sent per month , so

c=t/k

c=t/5 ---------- is the proportionality relationship.

For t=16 , c= 16/5 =$3.20

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Proportionality :brainly.com/question/11490054

Keywords: cell phone plan, month, international texts, proportional,paid

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4 0

3 years ago

a pack of toilet paper was originally $4.50 , it now cost $6.75. What is the solution to this problem?

Nitella [24]

2.25 is correct have a good day

5 0

2 years ago

please help me- this along with the last one and many more are worth a project grade and i need to pass school- quq

Alex

Each person would get $\frac{5}{8}$ pizza.

Solution:

Total quantity of pizza = $1\frac{7}{8}$

Number of persons shared = 3

To find how much pizza would each person get:

Let us first convert improper fraction into mixed fraction.

$$1\frac{7}{8}=\frac{1\times8 + 7}{8}=\frac{15}{8}$

Now divide the total quantity of pizza by the number persons shared.

$$\text{Quantity of pizza each person get}=\frac{(\frac{15}{8}) }{3}$

$$=\frac{15}{8\times3}$

$$=\frac{15}{24}$

Divide both numerator and denominator by 3.

$$=\frac{15\div3}{24\div3}$

$$=\frac{5}{8}$

Quantity of pizza each person get = $\frac{5}{8}$

Hence each person would get $\frac{5}{8}$ pizza.

5 0

3 years ago

Match the numerical expressions to their simplest forms.

Aloiza [94]

Answer:

$(a^6b^1^2)^\frac{1}{3}$ = $a^2b^4$

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$ = $a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$ = $a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$ = $ab^3$

Step-by-step explanation:

Simplify each of the expressions:

1

$(a^6b^1^2)^\frac{1}{3}$

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

$(a^6b^1^2)^\frac{1}{3}$

$a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}$

Simplify,

$a^2b^4$

2

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$

Rewrite as square roots:

$\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}$

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

$\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}$

Simplify,

$\sqrt{a^5b^3}*\sqrt{ab}$

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

$\sqrt{a^5b^3*ab}$

Simplify,

$\sqrt{a^6b^4}$

Since this operation is taking the square root, divide the exponents in half to do this operation:

$a^3b^2$

3

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

$(\frac{a^8}{b^-^4})^\frac{1}{4}$

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

$(a^8b^4)^\frac{1}{4}$

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

$\sqrt[4]{a^8b^4}$

SImplify, divide the exponents by (4) to simulate taking the quartic root,

$a^2b$

4

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

$(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}$