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ipn [44]
3 years ago
13

. If a, b, c are real numbers such that ac # 0

Mathematics
1 answer:
galben [10]3 years ago
7 0

Answer:

  if one equation has no real roots, the other must have real roots. Hence, at least one equation has real roots.

Step-by-step explanation:

The discriminant of the first equation is ...

  d1 = b^2 -4ac

The discriminant of the second equation is ...

  d2 = b^2 +4ac

__

Suppose the first equation has no real roots. Then ...

  d1 < 0

  b^2 -4ac < 0

  b^2 < 4ac

We know that b^2 is non-negative, so this means 4ac is positive. For that case,

  d2 = b^2 +4ac

is the sum of a positive number and a non-negative number so will be positive. When the discriminant is positive, there are two real roots.

When the first equation has no real roots, the second one must have two real roots.

__

Suppose the second equation has no real roots. Then ...

  d2 < 0

  b^2 +4ac < 0

  b^2 < -4ac

Again, b^2 is non-negative, so -4ac must be positive. For this case, the sum ...

  d1 = b^2 -4ac

is the sum of a non-negative and a positive number, so will be positive. The positive discriminant means there are two real roots.

When the second equation has no real roots, the first one must have two real roots.

One of these equations will have real roots, or not. If not, the other must have (distinct) real roots.

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Answer:

x = 36

Step-by-step explanation:

We have the equation (2/9)x + -2 = 6.

First, notice that adding a negative number is the same as subtracting by that number. So:

(2/9)x + -2 = 6

(2/9)x - 2 = 6

Now, we need to isolate the variable. Add 2 to both sides to cancel out the -2 on the left:

(2/9)x -2 + 2 = 6 + 2

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Now multiply both sides by 9/2 to cancel out the 2/9 on the left:

(9/2) * (2/9)x = 8 * (9/2)

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Thus, x = 36.

<em>~ an aesthetics lover</em>

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