If two dice are rolled one time, find the probability of getting doubles or a sum of 8.

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3-4x%7D%20%3D%20%5Cfrac%7B5%7D%7B2x%2B.25%7D" id="TexFormula1" title="\frac{8

BlackZzzverrR [31]

Step-by-step explanation:

$\frac{8}{3 - 4x} = \frac{5}{2x + .25} \\ 8(2x + .25) = 5(3 - 4x) \\ 16x + 2 = 15 - 20x \\ 16x + 20x = 15 - 2 \\ 36x = 13 \\ x = \frac{13}{36}$

7 0

2 years ago

brady has a card collection with 64 basketball cards, 32 football cards, and 24 baseball cards. he wants to arrange the cards in

forsale [732]

Answer:

8 piles for basketball

4 piles for football

3 piles for baseball

Step-by-step explanation:

1. Find the GCF of all three #s

2. 8 is the GCF, so divide each # by 8

3. You get the # of piles for each type of card

6 0

2 years ago

the effects of the above operations. Did this affect the inequality sign? Was it still true? Why or why not?

podryga [215]

Um, what operations? You didn't list any...

8 0

3 years ago

If a number minus 3 is at most 12, or 1 more than 2 times the number is at least 25, then the number must be less than or equal

dezoksy [38]

Answer:

The statement is true.

Step-by-step explanation:

Let us assume that x is the required number.

Now, given that the number minus 3 is at most 12.

Hence, x - 3 ≤ 12

⇒ x ≤ 15 ......... (1)

And also given that 1 more than 2 times the number is at least 25.

Hence, 2x + 1 ≥ 25

⇒ 2x ≥ 24

⇒ x ≥ 12 .......... (2)

Therefore, from equations (1) and (2) we get the number must be greater than or equal to 12 or less than or equal to 15.

So, the statement is true. (Answer)

3 0

3 years ago

Help me asap!!!!

qaws [65]

Answer (numbers needed in boxes, going from top to bottom):

1

-1

-3

3

Step-by-step explanation:

f(x) is another way of saying y. So, the table is asking, "when substituting these x values for the x's in the function, what does y equal?" So, to answer the question, substitute each x value into the equation and solve.

1) Start with the x value of 1. Substitute 1 for x in y = 2x - 1 and solve:

$y = 2(1)-1\\y = 2 - 1\\y = 1\\$

So, when x equals 1, y equals 1. Therefore, the first box on the top must be filled out with the number 1.

2) Do the same with the rest of the x values. Here are the steps to solve each one, going in order from the top towards the bottom:

x = 0

$y = 2(0) - 1\\y = 0 - 1\\y = -1$

x = -1

$y = 2(-1) - 1\\y = -2 -1 \\y = -3\\$

x = 2

$y = 2(2)-1\\y = 4-1\\y = 3\\$

8 0

2 years ago