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3 years ago

15

What is the measure of ∠B?

1 answer:

Alenkinab [10]3 years ago

7 0

Answer:

m<B = 60

Step-by-step explanation:

Exterior angle thm:

3x + 4x = 10x - 45

7x = 10x - 45

7x - 10x = -45

-3x = -45

x = 15

<B:

4x

4(15)

60

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Answer:

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Step-by-step explanation:

0+6y=7(y+6)-5

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3 years ago

Solve: <br>x + y = 7<br>3x - 2y = 11<br><br>By using Substituting method.

Salsk061 [2.6K]

$\large\underline{\sf{Solution-}}$

$\sf \longmapsto x + y = 7 \: \: - - - (i)$

$\sf \longmapsto 3x - 2y = 11 \: \: - - - (ii)$

<u>By first equation,</u>

$\sf \longmapsto x + y = 7$

$\sf \longmapsto x = 7 - y$

<u>Now, we can find the original value of y.</u>

$\sf \longmapsto 3x - 2y = 11$

$\sf \longmapsto 3(7 - y) - 2y = 11$

$\sf \longmapsto 21 - 3y - 2y = 11$

$\sf \longmapsto 21 - 5y = 11$

$\sf \longmapsto - 5y = 11 - 21$

$\sf \longmapsto - 5y = - 10$

$\sf \longmapsto y = \dfrac{ - 10}{ - 5}$

$\sf \longmapsto y = 2$

<u>Now, we can find the original value of x.</u>

$\sf \longmapsto x + y = 7$

$\sf \longmapsto x + 2 = 7$

$\sf \longmapsto x = 7 - 2$

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Therefore, the values of x and y are 5 and 2 respectively.

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3 years ago

Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t

Alina [70]

Answer:

~ $150=50e^{-0.01()20}$

~ $p(100)=\$127.7$

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week $P_{20}=\$150$

Marginal price-demand function $p'(x)=-0.5e-0.01x$

Generally the The Marginal price function is mathematically given by

$p'(x)=-0.5e^{-0.01x}$

$p(x)=\int-0.5e^{-0.01x}$

$p(x)=50e^{-0.001x}+C$

Therefore the equation when the demand is 20 TVs per week at $150 per TV

$150=50e^{-0.01()20}$

Giving

$p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}$

Therefore the Price when the demand is 100 TVs per week

$p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}$

$p(100)=\$127.7$

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3 years ago