Question

Christy is paid time-and-half hours worked in excess for 40 hours and double time for hours worked on Sunday. If Christy had grossed weekly wages of $592 for working 54 hours, 6 of which were on Sunday, what is her regular hourly rate?

Answer 1

Answer:

$9.25/hr

Step-by-step explanation:

Let regular hourly rate be "x"

Total hours worked = 54

6 of which are on Sunday (paid TWICE)

54 - 6 = 48

So, hours over 40 are:

48 - 40 = 8 hours (PAID 1.5 times)

So,

40 hours paid "x"

8 hours paid (1.5x)

6 hours paid (2x)

Which totals 592

We can write:

40x + 8(1.5x) + 6(2x) = 592

Now we can solve this for x to get our answer:

$40x + 8(1.5x) + 6(2x) = 592\\40x+12x+12x=592\\64x=592\\x=\frac{592}{64}\\x=9.25$

The regular hourly rate is $9.25/hr