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marin [14]
3 years ago
5

y=-2x+4y=−2x+4y, equals, minus, 2, x, plus, 4 Complete the missing value in the solution to the equation. ((left parenthesis ,-2

),−2)comma, minus, 2, right parenthesis
Mathematics
2 answers:
torisob [31]3 years ago
6 0

9514 1404 393

Answer:

  (3, -2)

Step-by-step explanation:

<u>Given</u>:

  y = -2x +4

<u>Find</u>:

  the value of x for y=-2

<u>Solution</u>:

  Put the value of y into the equation and solve for x:

  -2 = -2x +4 . . . . use -2 for y

  -6 = -2x . . . . . . . subtract 4

  3 = x . . . . . . . . . .divide by -2

The solution of interest is (3, -2).

lutik1710 [3]3 years ago
6 0

Answer:

The solution of interest is (3, -2).

Step-by-step explanation:

Hope this helps!

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(2
a_sh-v [17]

Answer:

The equation is,

(x+1)^{2} \times (x+2) = 0

Step-by-step explanation:

According to the question, the equation is cubic and have roots -1 (with multiplicity of 2) and -2.

So, the equation is,

(x+1)^{2} \times (x+2) = 0

[Since, when a , b , c are the roots of a cubic equation, the equation is

given by (x-a) \times (x-b) \times (x-c) = 0 ]

3 0
3 years ago
Find the perimeter of triangle PQR
Katyanochek1 [597]
27a+5.9+12.2 =Perimeter
5 0
3 years ago
Does evaluating an expression mean solving it?
masya89 [10]
Yes, it does! evaluating and solving an expression are the same thing!
4 0
3 years ago
Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground
Scorpion4ik [409]

Answer:

125.4\ \text{m/s}

Step-by-step explanation:

u = Initial velocity of baseball

\theta = Angle of hit = 30^{\circ}

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

y_0 = Height of hit = 2.5 ft

a_y = g = Acceleration due to gravity = 32.2\ \text{ft/s}^2

t = Time taken

Displacement in x direction

x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}

Displacement in y direction

y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}

The minimum initial velocity needed for the ball to clear the fence is 125.4\ \text{m/s}

5 0
3 years ago
What is the volume of a box measuring 1mX5mX6m?
Flauer [41]

Hey!

To find volume, you have to multiply the length, width, and height. All you have to do is multiply the 3 numbers together.

1 \times 5 \times 6 = 30

<em>The volume is 30 m³.</em>

Good luck and hope this helps! :)

6 0
3 years ago
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