let's check how much is it after 2 years firstly.
Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.
Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
First, we need to work out the left-hand side.
- find g(2) → g(2) = 2 - 1 which is 1
- next, find f(1) → f(1) = 1³ which is 1
Now, we can work out the right hand side.
- find f(-1) → f(-1) = -1³ which is -1
- then, find g(-1) → g(-1) = -1 - 1 = -2
Finally we can work out the full sum: 1 + -2 = -1.
Hope this helps!
It’s 1. Apparently my answer is not long enough so I’m making it longer :(:
Answer:
-2
Step-by-step explanation:
