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vodomira [7]
3 years ago
5

Choose the statistical question. * please help now

Mathematics
1 answer:
Burka [1]3 years ago
8 0

Answer:

The question, 'How much do the dogs in the pound weigh?' is the statistical question.

Hope this helps.

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In this picture, m<4=m<5=
djverab [1.8K]

Answer:

In the picture above.

Step-by-step explanation:

Using some identities for solution

I hope that it's a clear solution.

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2 years ago
-3x+6y=15 and -3x-2y=-1*
wariber [46]
How do you want this to be solved ?
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Find the values of x and y that make the following quadrilateral a parallelogram.
lidiya [134]

Answer:

x = 3 and y = 14

Step-by-step explanation:

opposite angles of a parallelogram are congruent. Hence,

1) 7y + 2 = 6y + 16

I. e. 7y - 6y = 16 - 2

I. e. y = 14

2) 8x + 8 = 6x + 14

I. e. 8x - 6x = 14 - 8

I. e. 2x = 6

I. e. x = 6/2

I. e. x = 3

7 0
3 years ago
Mathmerica Bank offers 2.1% interest compounded yearly
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Answer:

Total = 2,500 (1.021)^t

Step-by-step explanation:

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Total = amount (1 + rate)^time

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6 0
3 years ago
1. Contaminated water is subjected to a cleaning process. The concentration of the
Leokris [45]

Answer:

The concentration of pollutants in the water can be defined as the quotient between the mass of pollutants and the total mass of water.

Assuming that 1L of water weighs 1000 grams, we know that:

Mass of pollutants = 5mg = 0.005g.

Initial concentration = 0.005g/1000g = 0.000005

If we multiply this by 100%, we get the percentage:

0.000005*100% = 0.0005%

Now, the mass of pollutants decreases by 10% each hour.

So if initially, we have 5mg

After one hour, we will have: 5mg - 0.1*5mg = 5mg*(0.9).

After another hour, we will have: 5mg*(0.9) - 0.1*5mg*0.9 = 5mg*(0.9)^2.

And so on, then after n hours, the mass of pollutants will be:

M(n) = 5mg*(0.9)^n

Or we can write this in grams as:

M(n) = 0.005g*(0.9)^n

Then the concentration as a function of time in hours will be:

C(n) = M(n)/1000g = (0.005g/1000g)*(0.9)^n

Notice that the thing between the parentheses is the initial concentration, then if we write this in percentage form:

c(n) = 100%*(0.005g/1000g)*(0.9)^n = 0.0005%*(0.9)

The function that represents the concentration of polution in the water as a function of hours is:

c(n) = 0.0005%*(0.9)

6 0
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