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mina [271]
2 years ago
12

Dustin completed 3/8 of a homework that has 32 problems. how many problems did he complete

Mathematics
1 answer:
12345 [234]2 years ago
4 0

Answer:

12 is the answer

touch the picture and solve yr hw

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Start time: 9:17 A.M
pantera1 [17]
2:35 hope this help youuu
8 0
3 years ago
Read 2 more answers
1. Write each pair of parametric equations in rectangular form.<br> x = t +2<br> y = 5t + 7
hjlf

Step-by-step explanation:

t=x-2

y=5t+7

y=5(x-2)+7

y=5x-10+7

y=5x-3 is the required equation

3 0
2 years ago
Read 2 more answers
On a horizontal number lime, -6 is located to the left of -1. Enter an inequality that represents this statment.
Ann [662]

the expression "-6 is located to the left of -1" can be written as follow:

-6 < - 1

where the < symbol means "lower than", that is, you have "-6 is lower than -1".

6 0
10 months ago
The formula to find the period of orbit of a satellite around a planet is T^2=(4pi^2/GM)r^3 where r is the orbit's mean radius,
Natalija [7]
The answer is r= \sqrt[3]{GMT^{2}/4 \pi^{2}}

T^{2} = \frac{4 \pi^{2}}{GM} r^{3}

Move \frac{4 \pi^{2} }{GM} to the other side of the equation:
T^{2} /\frac{4 \pi^{2} }{GM} = r^{3}  \\ &#10;T^{2} *\frac{GM}{4 \pi^{2} } = r^{3}

Rearrange:
r^{3} = T^{2} *\frac{GM}{4 \pi^{2} } \\ &#10;r^{3}= \frac{T^{2} *GM}{4 \pi^{2} }  \\ &#10;r^{3}= \frac{GMT^{2}}{4 \pi^{2} } \\ &#10;r^{3} = GMT^{2}/4 \pi^{2}

Since x^{3}= \sqrt[3]{x}, then
r^{3} = GMT^{2}/4 \pi^{2} \\ &#10;r= \sqrt[3]{GMT^{2}/4 \pi^{2}}
3 0
3 years ago
Read 2 more answers
Y = -(x - 5) write the equation in slope-intercept form.
SOVA2 [1]

Answer:

y=-x+5

Step-by-step explanation:

6 0
3 years ago
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