2 years ago

Dustin completed 3/8 of a homework that has 32 problems. how many problems did he complete

Mathematics

1 answer:

12345 [234]2 years ago

4 0

Answer:

12 is the answer

touch the picture and solve yr hw

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pantera1 [17]

2:35 hope this help youuu

8 0

3 years ago

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1. Write each pair of parametric equations in rectangular form.<br> x = t +2<br> y = 5t + 7

hjlf

Step-by-step explanation:

t=x-2

y=5t+7

y=5(x-2)+7

y=5x-10+7

y=5x-3 is the required equation

3 0

2 years ago

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On a horizontal number lime, -6 is located to the left of -1. Enter an inequality that represents this statment.

Ann [662]

the expression "-6 is located to the left of -1" can be written as follow:

-6 < - 1

where the < symbol means "lower than", that is, you have "-6 is lower than -1".

6 0

11 months ago

The formula to find the period of orbit of a satellite around a planet is T^2=(4pi^2/GM)r^3 where r is the orbit's mean radius,

Natalija [7]

The answer is $r= \sqrt[3]{GMT^{2}/4 \pi^{2}}$

$T^{2} = \frac{4 \pi^{2}}{GM} r^{3}$

Move $\frac{4 \pi^{2} }{GM}$ to the other side of the equation:
$T^{2} /\frac{4 \pi^{2} }{GM} = r^{3} \\ 
T^{2} *\frac{GM}{4 \pi^{2} } = r^{3}$

Rearrange:
$r^{3} = T^{2} *\frac{GM}{4 \pi^{2} } \\ 
r^{3}= \frac{T^{2} *GM}{4 \pi^{2} } \\ 
r^{3}= \frac{GMT^{2}}{4 \pi^{2} } \\ 
r^{3} = GMT^{2}/4 \pi^{2}$

Since $x^{3}= \sqrt[3]{x}$ , then
$r^{3} = GMT^{2}/4 \pi^{2} \\ 
r= \sqrt[3]{GMT^{2}/4 \pi^{2}}$

3 0

3 years ago

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Y = -(x - 5) write the equation in slope-intercept form.

SOVA2 [1]

Answer:

y=-x+5

Step-by-step explanation:

6 0

3 years ago