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Savatey [412]
4 years ago
14

IMG_1444.PNG ( please answer these WITH YOUR WORK SHOWING!) it’s okay if you don’t know them all but please some of them answere

d would be appreciated!!!

Mathematics
1 answer:
Setler79 [48]4 years ago
3 0
#18)  (√2)/(2y)
#19)  7x/5
#20)  (2√5)/5
#21)  (3√5)/5
#22)  √5/b
#23)  (2√(2n))/n
#24)  (2√15)/15m

For #18:
\sqrt{\frac{18y}{36y^3}}=\sqrt{\frac{1}{2y^2}}=\frac{1}{y\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{2y}

#19:
\sqrt{\frac{49x^5}{25x^3}}=\sqrt{\frac{49x^2}{25}}=\frac{7x}{5}

#20:
\frac{\sqrt{12}}{\sqrt{15}}=\frac{2\sqrt{3}}{\sqrt{15}}\times \frac{\sqrt{15}}{\sqrt{15}}=\frac{2\sqrt{45}}{15}=\frac{6\sqrt{5}}{15}=\frac{2\sqrt{5}}{5}

#21:
\frac{\sqrt{72}}{\sqrt{40}}=\frac{6\sqrt{2}}{2\sqrt{10}}=\frac{3\sqrt{2}}{\sqrt{10}}\times \frac{\sqrt{10}}{\sqrt{10}}=\frac{3\sqrt{20}}{10}=\frac{6\sqrt{5}}{10}=\frac{3\sqrt{5}}{5}

#22:
\sqrt{\frac{25b}{5b^3}}=\sqrt{\frac{5}{b^2}}=\frac{\sqrt{5}}{b}

#23:
\sqrt{\frac{24}{3n}}=\sqrt{\frac{8}{n}}=\frac{2\sqrt{2}}{\sqrt{n}}\times \frac{\sqrt{n}}{\sqrt{n}}=\frac{2\sqrt{2n}}{n}

#24:
\sqrt{\frac{8}{30m^2}}=\sqrt{\frac{4}{15m^2}}=\frac{2}{m\sqrt{15}}\times \frac{\sqrt{15}}{\sqrt{15}}=\frac{2\sqrt{15}}{15m}
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babunello [35]

Answer:

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3 years ago
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A person standing d=145 centimeters from a mirror notices that the angle of depression from his eyes to the bottom of the mirror
Serggg [28]

The length of the mirror is 64.52 cm

<u>Explanation:</u>

Given:

Distance of the person from the mirror = 145cm

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For the angle of depression:

tan(14) = \frac{BC}{BO} \\\\0.25 = \frac{BC}{145} \\\\BC = 36.25 cm

Total length of the mirror, AC = AB + BC

                                              = 28.275 + 36.25cm

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4 years ago
What percent of 56 is 35 shirts
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Divide 35 and 56:
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3 years ago
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