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3 years ago

Find the orbital period (in years) of an asteroid whose average distance from the sun is 27

1 answer:

7 0

Using Kepler's third law which is defined as the square of the average distance is directly proportional to the cube of the period. It is expressed as P^2 = a^3, Given that the a = average distance is given, the period would be much easier to compute. P = sqrt(27^3) = 140

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A 3.8 object is lifted 12 meters. how much work is performed during the lifting?

Delicious77 [7]

I believe the answer would be 446.9 J.

7 0

4 years ago

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A magnet of mass 0.20 kg is dropped from rest and falls vertically through a 35.0 cm copper tube. Eddy currents are induced, cau

topjm [15]

Answer:

0.58 J

Explanation:

We know that Total energy is conserved.

Initial Kinetic energy + Initial potential energy = final kinetic energy+ final potential energy + dissipated heat energy

Initial kinetic energy = 0 ( magnet is at rest initially)

Initial Potential energy = m g h = (0.20 kg)(9.81 m/s²)(0.35 m) = 0.69 J

Final kinetic energy = 0.5 m v² = 0.5 ×0.20 kg × 1.10 m/s = 0.11 J

Final potential energy = 0

∴ Dissipated heat energy = (0.69 -0.11) J = 0.58 J

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3 years ago

What is the value of relative humidity when the air is saturated?

Brut [27]

Answer:

100 percent

Explanation:

Relative humidity is the water-vapour content of the air relative to its content at saturation. Saturated air, for example, has a relative humidity of 100 percent, and near the Earth the relative humidity very rarely falls below 30 percent.

3 0

3 years ago

A car starts from rest and after 7 seconds it is moving at 69 m/s. What is the car’s average acceleration?

a_sh-v [17]

Answer:

6m/s squared

Explanation:

We'll use a simple kinematic equation to solve this.

v=v⊕at

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4 years ago

A uniform bridge 20.0 m long and weighing 400000 N is supported by two pillars located 3.00 m from each end. If a 19600 N car is

Svetradugi [14.3K]

Answer:

P = 238475 N

Q = 181125

Explanation:

From the diagram attached below,

For the bridge to be at equilibrium,

Sum of upward force = sum of downward force

P+Q = 400000+19600

P+Q = 419600.................. Equation 1

Taking moment about support A

sum of clockwise moment = sum of anti clockwise moment.

400000(10-3)+19600(8-3) = Q(20-6)

2800000+98000 = 16Q

2898000 = 16Q

Q = 2898000/16

Q = 181125 N.

Substitute the value of Q into equation 1

P+181125 = 419600

P = 419600-181125

P = 238475 N.

Hence, support A exert a force of 238475 N and support B exert a force of 181125 N

7 0

3 years ago

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