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suter [353]
3 years ago
12

Set up an equation and solve the following

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Here's an answer! :)

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How to 2 ft 5 in plus 9 in
Elina [12.6K]
1 ft equals 12 in. So 2ft equals 24 in. 24 in plus 5 in equals 29 in, and 29 in plus 9 in equals 38 in. 38/12 equals 3 ft 2 in.
4 0
3 years ago
Find the slope and y intercept
zepelin [54]

Answer:

slope = -1

y intercept (0,-2)

Step-by-step explanation:

We can use the two points to find the slope

(-4,2) and (1,-3)

m = ( y2-y1)/(x2-x1)

    = (-3 -2)/(1 - -4)

   = -5 /(1+4)

   = -5/5

 - 1

The y intercept is where it crosses the y axis

y intercept is (0,-2)

5 0
3 years ago
A television newscaster from a 24-hour news station wants to estimate the number of hours per day its viewers watch
topjm [15]

Answer:

This isn't the best worded question but from what I understand a larger sample size decreases the margin of error. If he would like a more accurate answer a larger sample size of the viewers will give more accurate answers.

Step-by-step explanation:

4 0
3 years ago
Please hurry attachment below will Brainly if answer correctly 30 POINTS
Rzqust [24]
Put everything into a calculator to change to decimal form to make things easier:
27/5=5.4
5.36=5.36
5 3/5=5.6
33/6=5.5
So now in order to least to greatest it would be:
5.36, 27/5, 33/6, 5 3/5
6 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
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