How do I solve this equation? If 3t-7=5t then 6t=a 21b-7c-21d-42

1 answer:

5 0

$3t-7=5t \ \ \ \ \ |\hbox{subtract 3t} \\
-7=2t \ \ \ \ \ \ \ \ |\hbox{multiply by 3} \\
-21=6t \\ \\
\boxed{6t=-21} \\
\hbox{answer C}$

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