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TEA [102]
3 years ago
14

Isabell drove 819 miles in 13 hours. at the same rate how many miles would she drive in 7 hours

Mathematics
2 answers:
ahrayia [7]3 years ago
8 0

Answer:

441 miles

Step-by-step explanation:

Rate of the Car: 819/13 = 63mph

Miles Driven in 7 Hours: 63*7 = 441 miles

Reika [66]3 years ago
7 0

Answer:

441 miles

Step-by-step explanation:

* means multiply

819/13 = x/7

13 * x = 819 * 7

13x = 5733

x = 5733 ÷ 13

x = 441

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The answer would be 44,800 if you want to round the hundreds place
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If 1/4 of x is 16, what is 3/4 of x! Justify your answer in more than one way
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It takes Benjamin 28 minutes to mow 2 lawns. Assuming the lawns are the same size and Benjamin works at the same speed, about ho
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Answer:

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Suppose that an individual has a body fat percentage of 14.5% and weighs 167 pounds. How many pounds of her weight is made up of
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The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
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