Check all solutions to the equation. If there are no solutions, check 'None." x² = 64
1 answer:
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9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
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If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
We have that an inverse variation in a function is given by:
We must find the value of the constant k.
To do this, we substitute the values of x1 = 12, y1 = 15.
We have then:
Clearing k we have:
Substituting the value of k we have that the inverse variation is:
For y2 = 3 we have:
Clearing x2 we have:
Answer:
We must find the value of the constant k.
To do this, we substitute the values of x1 = 12, y1 = 15.
We have then:
Clearing k we have:
Substituting the value of k we have that the inverse variation is:
For y2 = 3 we have:
Clearing x2 we have:
Answer: