Answer:
Step-by-step explanation:
To make the problem easier to solve, we will set it up as the equation of the length of time of each class times the number of classes equals the total amount of minutes. However, since we don't know the number of classes, we'll symbolize our two unknowns with two variables.
75x + 45y = 705
(75x + 45y)/15 = 705/15
5x + 3y = 47
y = (47-5x)/3
It looks like we can't simplify the equation any more, so now it is a matter of trial and error. The minimum number of Saturday classes means the maximum number of weekday classes. We first will test for the maximum by assuming there are no Saturday classes, then will work our way up until x is an integer.
If x = 0
(47-5(0))/3 = 47/3 = 15.6666
If x = 1
(47-5(1))/3 = 42/3 = 14
This works. Therefore, the maximum number of weekday classes is 14, or choice b.
Answer:
Its x^2 over 81 + y^2 over 18 = 1
major: (9,0) and (-9,0)
minor: (0,4.24) and (0,-4.24)
<h2>D ON EDGE 21' </h2>
Step-by-step explanation:
I took the mf test babes <3
Question five
D is correct
10x-35
Question six
These are true
4(4y+7)
2(8y+14)
8(2y+4) - 4
2y+7(2y+4)
good luck
3
absolute value takes the negative away
Answer:
$10.348
Step-by-step explanation:
(3.98)(2.6)= 10.348
