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Taya2010 [7]
3 years ago
8

Pls help me answer this i really need it :/

Mathematics
2 answers:
tekilochka [14]3 years ago
8 0
The answer is C
Step by step explanation
Mrac [35]3 years ago
5 0

Answer:

Answer is c

Step-by-step explanation:

Here's the explanation hope you understand my concept

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Given the position of the particle, what the position(s) of the particle when it’s at rest
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The position function of a particle is given by:

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The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

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The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

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Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

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