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PSYCHO15rus [73]
3 years ago
7

Two years ago, Rita was three times older than Cheryl. In 3 years, Rita will be twice older than Cheryl. How old are the girls n

ow?
Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

Cheryl's age = x = 7 years

Rita's age = y = 17 years

Step-by-step explanation:

Let

Cheryl's age = x

Rita's age = y

Two years ago, Rita was three times older than Cheryl

(y - 2) = 3(x - 2)

y - 2 = 3x - 6

y = 3x - 6 + 2

= 3x - 4

y = 3x - 4

In 3 years, Rita will be twice older than Cheryl

(y + 3) = 2(x + 3)

y + 3 = 2x + 6

y = 2x + 6 - 3

= 2x + 3

y = 2x + 3

Equate both equations

3x - 4 = 2x + 3

Collect like terms

3x - 2x = 3 + 4

x = 7 years

Substitute x = 7 into

y = 2x + 3

= 2(7) + 3

= 14 + 3

= 17

y = 17 years

Cheryl's age = x = 7 years

Rita's age = y = 17 years

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2 years ago
Find the average velocity of the function over the given interval.
snow_lady [41]

Answer:

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

             Average velocity  = \frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx

                               =    \frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx

now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

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by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

6 0
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Answer:

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Step-by-step explanation:

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