Answer:
P(A) ∪ P(B) ⊆ P(A ∪ B) can be proved when ∈ P ( A U B )
Step-by-step explanation:
To Prove that P(A) ∪ P(B) ⊆ P(A ∪ B) is attached below and also a counter example to prove that we do not always get an equality is attached below as well
Help it is due tomorrow morning
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