Answer:
(14a+3, 21+4) = 1
Step-by-step explanation:
We are going to use the Euclidean Algorithm to prove that these two integers have a gcd of 1.
gcd (14a + 3, 21a + 4) = gcd (14a+3, 7a + 1) = gcd (1, 7a+1) = 1
Therefore,
(14a + 3, 21a + 4) = 1
Answer is below this comment :D
Answer:
1 and 2
Step-by-step explanation:
If y was 1: -2 x 1 + 18 = -2 + 18
= 16 This works
If y was 2: -2 x 2 + 18 = -4 + 18
= 14 This works
If y was 3: -2 x 3 + 18 = -6 + 18
= 12 This does not work since -2y + 18 has to be <u>greater</u> than 12.
Answer:
Step-by-step explanation:
Answer: A
Step-by-step explanation:
A rhombus is a quadrilateral with all sides equal in length. A square is a quadrilateral with all sides equal in length and all interior angles right angles. Thus a rhombus is not a square unless the angles are all right angles. ... A square however is a rhombus since all four of its sides are of the same length.
A square is a quadrilateral with all four angles right angles and all four sides of the same length. So a square is a special kind of rectangle, it is one where all the sides have the same length. Thus every square is a rectangle because it is a quadrilateral with all four angles right angles.
