Answer:
P(A) ∪ P(B) ⊆ P(A ∪ B) can be proved when
∈ P ( A U B )
Step-by-step explanation:
To Prove that P(A) ∪ P(B) ⊆ P(A ∪ B) is attached below and also a counter example to prove that we do not always get an equality is attached below as well
Answer:
!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!
Step-by-step explanation:
Does not compute *SPUTTER SPUTTER CRASH!*
<span>y + 4 ≤ 0
----------------------
Subtract 4 from each side
</span><span>y + 4 - 4 ≤ 0 - 4
</span>y ≤ -4
y ≤ -4 is the answer
Answer:
11
Step-by-step explanation:
55/11=5