The graph of the equation given by y=-cos³θ will be as follows:
Answer:
if you can use the app photomath or m.a.t.h. w.a.y
Step-by-step explanation:
Answer:
Dist = 45 m/h * x h
Step-by-step explanation:
We know a speed is a measure of distance over time: speed = dist / time
In this case, we are looking for a distance expressed in terms of time.
So, we only need to modify the formula a bit: dist = speed * time
We don't know the time (which will be a variable), but we know their speed. So, the formula becomes:
Dist = 45 m/h * x h
Enter the number of hours in the formula and that will give you an approximation of the distance traveled within that time (approximation since our result will be rely on an average).

which means there is some integer

for which

.
Because

and

, there are integers

such that

and

, and

We have

, which means there are four possible choices of

:
1, 42
2, 21
3, 14
6, 7
which is to say there are also four corresponding choices for

:
9, 378
18, 189
27, 126
54, 63
whose sums are:
387
207
153
117
So the least possible value of

is 117.
-0.05 is larger. Since they're negative, you're going by which is closer to 0 rather than farther. -0.05 is closer to 0 on a number line, so it's larger than -0.25.