Given 4 points A, B, C, D where no 3 points are collinear, any 2 points have a distance greater than 10. Prove that there exist
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Answer:
No
Step-by-step explanation:
Given
Quadrilateral A: 2,3,5 and 6
Quadrilateral B: 4,5, 8 and 10
Required
Determine if one is a scale of another
To do that, we have to divide the corresponding lengths to give ratio.
Considering Side of A = 2 and Side of B = 4
Considering Side of A = 3 and Side of B = 5
There's no need to check further, since the two ratios calculated so far do not have the same value;
<em>Hence, one quadrilateral is not a scale of the other</em>