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bezimeni [28]
3 years ago
14

What is equivalent to -1/4 - 5/3

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

-3/12 - 20/12 is equivalent to -1/4 - 5/3

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Can somebody help me with the rest of the question
kari74 [83]

Shop #1 has the best price for 21 pizzas because it is $105, while Shop #2 costs $147 for 21 pizzas which is a lot more money. they would save $42, which is 147-105=42. hope this helps:)

5 0
3 years ago
The temperature in Baku, Azerbaijan dropped over five hours from zero degrees Fahrenheit to negative fifteen degrees Fahrenheit.
e-lub [12.9K]

Answer:

its either 3 or -3 hopefully someone in the comments can tell which

Step-by-step explanation:

6 0
3 years ago
Help solve for x. round to the nearest tenth​
Llana [10]

Answer:

x = 3.7

Step-by-step explanation:

Apply trigonometric function to find x

Reference angle = 24°

Opposite = x

Hypotenuse = 9

This, apply SOH:

Sin 24 = Opp/Hyp

Sin 24 = x/9

9 × Sin 24 = x

3.66062979 = x

x = 3.7 (nearest tenth)

4 0
2 years ago
This problem uses the teengamb data set in the faraway package. Fit a model with gamble as the response and the other variables
hichkok12 [17]

Answer:

A. 95% confidence interval of gamble amount is (18.78277, 37.70227)

B. The 95% confidence interval of gamble amount is (42.23237, 100.3835)

C. 95% confidence interval of sqrt(gamble) is (3.180676, 4.918371)

D. The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

Step-by-step explanation:

to)

We will see a code with which it can be predicted that an average man with income and verbal score maintains an appropriate 95% CI.

attach (teengamb)

model = lm (bet ~ sex + status + income + verbal)

newdata = data.frame (sex = 0, state = mean (state), income = mean (income), verbal = mean (verbal))

predict (model, new data, interval = "predict")

lwr upr setting

28.24252 -18.51536 75.00039

we can deduce that an average man, with income and verbal score can play 28.24252 times

using the following formula you can obtain the confidence interval for the bet amount of 95%

predict (model, new data, range = "confidence")

lwr upr setting

28.24252 18.78277 37.70227

as a result, the confidence interval of 95% of the bet amount is (18.78277, 37.70227)

b)

Run the following command to predict a man with maximum values ​​for status, income, and verbal score.

newdata1 = data.frame (sex = 0, state = max (state), income = max (income), verbal = max (verbal))

predict (model, new data1, interval = "confidence")

lwr upr setting

71.30794 42.23237 100.3835

we can deduce that a man with the maximum state, income and verbal punctuation is going to bet 71.30794

The 95% confidence interval of the bet amount is (42.23237, 100.3835)

it is observed that the confidence interval is wider for a man in maximum state than for an average man, it is an expected data because the bet value will be higher than the person with maximum state that the average what you carried s that simultaneously The, the standard error and the width of the confidence interval is wider for maximum data values.

(C)

Run the following code for the new model and predict the answer.

model1 = lm (sqrt (bet) ~ sex + status + income + verbal)

we replace:

predict (model1, new data, range = "confidence")

lwr upr setting

4,049523 3,180676 4.918371

The predicted sqrt (bet) is 4.049523. which is equal to the bet amount is 16.39864.

The 95% confidence interval of sqrt (wager) is (3.180676, 4.918371)

(d)

We will see the code to predict women with status = 20, income = 1, verbal = 10.

newdata2 = data.frame (sex = 1, state = 20, income = 1, verbal = 10)

predict (model1, new data2, interval = "confidence")

lwr upr setting

-2.08648 -4.445937 0.272978

The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

4 0
3 years ago
jesse is putting a ribbon around a square frame. He uses 24 inches of ribbon. How long is each side of the frame
OverLord2011 [107]
Answer
24÷4=6
So six
7 0
2 years ago
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