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Rom4ik [11]
3 years ago
10

Test pls help! thank you​

Mathematics
2 answers:
natita [175]3 years ago
5 0

Answer:

The Answer is 5/12

Pls mark as brainliest

Alex73 [517]3 years ago
3 0

Answer:

A

Step-by-step explanation:

find the lowest common multiple, which is 12

subtract 3 from 8 = 5

and voila, 5/12

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If g(x)= 3x-1 solve for x when g(x)=-20.
Nadya [2.5K]

Good evening

Answer:

x=\frac{-19}{3}

Step-by-step explanation:

g(x) = -20

⇔

3x-1 = -20

⇔

3x = -20 + 1

⇔

3x = -19

⇔

x = -19/3

____________________

:)

3 0
3 years ago
Why do purely competitive markets tend to benefit consumers over producers? Companies control quality and supply. Companies work
Tom [10]
In general, purely competitive markets tend to benefit consumers over producers because "<span>Consumers control price through demand". Although perfect competition is practically impossible. </span>
3 0
3 years ago
Read 2 more answers
Please help! posted picture of question
o-na [289]
C. 5x - 2y = 16 is your answer

plug in each point into the equation.

(2, -3)

x = 2, y = -3

5(2) - 2(-3) = 16
10 + 6 = 16
16 = 16 (True)

(4,2)

x = 4, y = 2

5(4) - 2(2) = 16
20 - 4 = 16
16 = 16 (True)


hope this helps
4 0
3 years ago
Read 2 more answers
Hailey earned $90 for working 12 hours. How much can she earn for working 29 hours
Afina-wow [57]

Answer:

She will make 217.50 for 29 hours

Step-by-step explanation:

We can find the rate per hour by dividing the money by the number of hours

90/12 =7.5 per hour

She makes 7.50 per hour

If she works 29 hours

Money = rate * hours

           = 7.5 * 29

           =217.50

She will make 217.50 for 29 hours

8 0
3 years ago
Read 2 more answers
Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2
34kurt
\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta

which follows from the usual change of coordinates via

\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}

and Jacobian determinant

|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|

Swap the order, so that the integral is

\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr

and now let \sigma=r\cos\theta, so that \mathrm d\sigma=-r\sin\theta. Now, you have

\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2
7 0
3 years ago
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