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Rom4ik [11]
3 years ago
10

Test pls help! thank you​

Mathematics
2 answers:
natita [175]3 years ago
5 0

Answer:

The Answer is 5/12

Pls mark as brainliest

Alex73 [517]3 years ago
3 0

Answer:

A

Step-by-step explanation:

find the lowest common multiple, which is 12

subtract 3 from 8 = 5

and voila, 5/12

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Help please with this math question
Vanyuwa [196]
To solve this question, simply use the formula to find the volume of the cylinder,

V = Pi r^2 • h

V = 3.14 • 4^2 • 4.

Then compare the value for volume to the closest number on the number line. Is it in between 2 numbers, exactly one number on the number line or very close to one number as in the number line.






8 0
3 years ago
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Suppose Mahkah makes a Native American lunch in a pot that is shaped like a right cylinder. If
Harman [31]

The pot can hold 5.23 quarts

Step-by-step explanation:

  • Step 1: Find the volume of the right cylinder shaped pot.

Diameter of the pot = 8 in

⇒ Radius = 4 in

Height = 6 in

⇒ Volume of the pot = πr²h = 3.14 × 4² × 6

                                   = 301.44 in³

  • Step 2: Convert inches to quarts.

1 in³ = 0.017316 liquid quarts

⇒ 301.44 in³ = 301.44 × 0.017316 = 5.23 quarts

6 0
3 years ago
In order to apply the law of sines to find the length of the side of a triangle, it is enough to know which of the following?
larisa86 [58]

Answer:

We must have two angles and a side.

A is the correct option.

Step-by-step explanation:

For any triangle ABC,  the law of sine is given by

\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}

From this formula it is clear that in order to find the length of the side of the triangle, we must have two angles and a side.

Let us understand this by assuming that we need to find a (length of the side). From the formula, we have

\frac{a}{\sin A}=\frac{b}{\sin B}\\\\a=\frac{b\sin A}{\sin B}

Thus, to find the length a, we must have b, sin A and sin B.

Hence, o find the length of the side of the triangle, we must have two angles and a side.

3 0
4 years ago
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F(x)=-9x^2-2x and g(x)=3x^2+6x-9, find (f-g)(x) and (f-g)(-4)
Sergio039 [100]

Answer:

(f-g)(x) = -12x^{2} - 8x + 9

(f-g)(-4) = -151

Step-by-step explanation:

To find f-g(x) we subtract the common terms. So

f(x) = -9x^{2} - 2x

g(x) = 3x^{2} + 6x - 9

(f-g)(x)

(f-g)(x) = f(x) - g(x) = -9x^{2} - 2x - (3x^{2} + 6x - 9) = -9x^{2} - 2x - 3x^{2} - 6x + 9 = (-9 - 3)x^{2} + (-2 - 6)x + 9 = -12x^{2} - 8x + 9

(f-g)(-4)

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5 0
4 years ago
Need help with this<br>​
AleksandrR [38]

Step-by-step explanation:

\cos( \beta  )  +  \sin( \beta )  \tan( \beta )  =  \sec( \beta )

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\cos( \beta )  +  \frac{ \sin {}^{2} ( \beta ) }{ \cos( \beta ) }

\frac{ \cos {}^{2} ( \beta ) }{cos \beta }  +  \frac{ \sin {}^{2} ( \beta ) }{ \cos( \beta ) }

\frac{1}{ \cos( \beta ) }

=  \sec( \beta )

3 0
3 years ago
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