7. In right triangle BCD, BD12, mLC 90, andmLDBC47. Find DC to the nearest tenth47

What is the length of a squares diagonal when the sides are 1 km

PIT_PIT [208]

Answer:

As per given Information

Side of square = 1 Km

we have to find the length of diagonal of square .

For finding the length of diagonal of square we will use formale

Length of Diagonal = Side√2

Putting the value we get

↠ Length of Diagonal = 1√2 Km

So, the length of diagonal of square is 1√2 Km

7 0

2 years ago

Jordan earned $200 this month delivering newspapers. His mom said he must put 20% into his savings account. He wants to buy head

Dennis_Churaev [7]

Answer:

Yes, his calculation is reasonable. He will have about $16.67 left.

Step-by-step explanation:

200 - (200 * .2) = $160 <em>Subtract money for savings</em>

99.95 + (99.95 * .07) + (17*2) + (17 * .07) + (17 * .07) = $143.33 <em>Add taxes</em>

160 - 143.33 = $16.67 <em>Subtract money for purchases from money left after savings</em>

6 0

2 years ago

-2. H(x) is the transformation of the parent

elena-s [515]

If the function f(x) is translated 7 units right and 8 units up, then the equation of h(x) is h(x) = $(x+7)^2$ + 8

The given function is

f(x) = $x^2$

Here f(x) is translated 7 units right and 8 units up

The translation is the process of changing the coordinates of the shape in the graph

The given function is

f(x) = $x^2$

First the function is translated 7 units right

Then the function will become

f(x) = $(x+7)^2$

Then the function is translated 8 units up

Then the function will become

h(x) = $(x+7)^2$ + 8

Hence, if the function f(x) is translated 7 units right and 8 units up, then the equation of h(x) is h(x) = $(x+7)^2$ + 8

Learn more about translation here

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6 0

7 months ago

How many solutions does this linear system have? y = y equals StartFraction 2 over 3 EndFraction x plus 2. X 2 6x – 4y = –10 one

nordsb [41]

The system of equations provides a unique solution(one solution) at (-0.6, 1.6).

<h2>Given to us,</h2>

$y=\dfrac{2}{3}x+2$
$6x-4y=-10$

<h3>Equation 2</h3>

As we already have the value of y from equation 1, substitute its value in equation 2,

$6x-4y=-10$

$6x-4(\dfrac{2}{3}x+2)=-10$

$6x-\dfrac{8}{3}x-8=-10$

$\dfrac{6x}{1}-\dfrac{8}{3}x=-10+8$

$\dfrac{6x\times 3}{1\times 3}-\dfrac{8}{3}x=-2$

$\dfrac{18x-8x}{3}=-2$

$10x=-6\\$

$x=\dfrac{-6}{10} \\\\x=-0.6$

<h3>Equation 1,</h3>

$y=\dfrac{2}{3}x+2$

substitute the value of x in equation 1,

$y=\dfrac{2}{3}(\dfrac{-6}{10})+2\\\\y = \dfrac{-2}{5}+2\\\\y= \dfrac{-2+10}{5}\\\\y = \dfrac{8}{5}\\\\y=1.6$

As we can see the system of equations provides a unique solution(one solution) at (-0.6, 1.6).

Learn more about the system of equations:

brainly.com/question/12895249

3 0

2 years ago

you make homemade lip balm about 11% of the lip balm is made from beeswax you make 4 2/5 teaspoons of of the lip balm about how

o-na [289]

≈ 1/2 teaspoon
4 2/5 * .11 = .484 teaspoon

7 0

2 years ago