Answer:
I think it's around 31
Step-by-step explanation:
8 litres (amount of 20% solution needed) and 7 litres for (amount of 50% solution needed)
<u>Step-by-step explanation:</u>
Let consider ‘x’ for 20% acid solution and (15 – x) for 50% acid solution. And so, the equation would be as below,
20% in x + 50% in (15 – x) = 15 litres of 34%
Convert percentage values, we get
0.20(x) + 0.50 (15 – x) = 15 (0.34)
0.20 x + 7.5 – 0.50 x = 5.1
-0.3 x + 7.5 = 5.1
0.3 x = 7.5 – 5.1
0.3 x = 2.4
![x = \frac{2.4}{0.3} = 8 litres (amount of 20 \% solution needed)](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B2.4%7D%7B0.3%7D%20%3D%208%20litres%20%28amount%20of%2020%20%5C%25%20solution%20needed%29)
Apply ‘x = 8’ value in (15 – x) we get,
15 – 8 = 7 litres
The value of 7 litres for (amount of 50% solution needed)
9514 1404 393
Answer:
- 1,563.5 in³
- 904.8 yd³
- 2,144.7 mm³
- 1,288.2 cm³
- 434.9 in³
Step-by-step explanation:
The formula for the volume of a sphere is ...
V = (4/3)πr³
When you have several of these calculations to do, it is convenient to let a graphing calculator or spreadsheet do them. A spreadsheet can do the rounding for you, too. The results are attached. The units are the cube of the units of the radius.
<u><em>Example calculation</em></u>:
(4) Radius = diameter/2 = 13.5 cm/2 = 6.75 cm
V = (4/3)π(6.75 cm)³ = 4.18879 × 307.547 cm³ = 1288.2 cm³
Note that the constant (4/3)π ≈ 4.18879 remains the same for each calculation. All you need to do is multiply that by the cube of the radius.
Yes it is, 6.52 and 6.52 are the same but one has an extra 0.
No solutions. Subtract 2x from both sides and you get 3x-2=3x+8, which is impossible.