Answer:
From the following equation, the zero 3 has multiplicity with 1 and the zero -1 has multiplicity with 1 and the zero 2 has multiplicity with 5. The degree of the polynomial is 7.
Step-by-step explanation:
The following equation are:
p(x) = (x -3)(x + 1)(x - 2)(x - 2)(x - 2)(x - 2)(x - 2)
Then, the multiplicity of the equation:
p(x) = (x -3)(x + 1)(x - 2)^5
In the following equation, the zero 3 has multiplicity with 1 and the zero -1 has multiplicity with 1, and the zero 2 has multiplicity with 5.
Then the degree of the all polynomials is highest degrees in every term.
So, first we have to expand it:
p(x) = (x -3)(x + 1)(x - 2)^5
p(x) = (x -3)(x + 1)(x - 2)(x - 2)(x - 2)(x - 2)(x - 2)
p(x) = (x^2 + x - 3x - 3)(x^2 - 4x - 4)(x^2 - 4x - 4)(x-2)
p(x) = (x^4 - 6x^3 + 9x^2 + 4x - 12)(x^3 - 6x^2 + 12x - 8)
p(x) = x^7 - 12x^6 + 57x^5 - 130x^4 + 120x^3 + 48x^2 - 176x + 96
so, then the degree of the following equation is 7