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Orlov [11]
2 years ago
9

I know this is silly but I wasn’t fought correctly how to read clocks and I’m struggling right now.

Mathematics
2 answers:
AleksandrR [38]2 years ago
6 0

Answer:

<h2><em><u>10</u></em><em><u>:</u></em><em><u>25</u></em></h2>

Step-by-step explanation:

Since,

The hour hand is just slightly up than 10 and minute hand is on 5.

Which denotes <em><u>10:25</u></em>

Gnoma [55]2 years ago
4 0

Answer:

its 10:25 :)

Step-by-step explanation:

hope this helps!

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The sum of the angles of a triangle is 180°. If one angle of a triangle measures x and the second angle measures
serious [3.7K]

Answer:

the third angle= 180-x-(4x+15)

Step-by-step explanation:

if we subtract the two other angles the result will be the measure of the last one

4 0
3 years ago
The pointer of the vibration measuring instrument is observed to move between the 0.1 and0.3 marks on the vertical scale, when s
Norma-Jean [14]

Answer:

Step-by-step explanation:

Given points moves b/w 0.1 of 0.3 marks Hence amplitude is 0.2

Also , frequency (w) = 100 rad/s.

Natural frequency (wn) = √K/m

K = 20 N/mm x 1000mm/1m = 20000N/M

W = 1000mm/1m = 20,000N/M

FormulaX = FolK/1 - (w/wn)²

0.2 = b/20000/1 - (100/50)²

Given forcing frequency was doubled, W1 = 2 x 100=200rad/s

X1 =b/20,000/1 - (200/20)²

0.2/11 = 1 - (200/50)²/1 - (100/50)² = 0.2/11 = -15^5– 3

X1 = 0.04

8 0
3 years ago
–5(v + 65) = -65 v = ____
labwork [276]

Answer:

v = -52

Step-by-step explanation:

Divide both sides by -5

v + 65 = 13

v = 13 - 65

v = -52

4 0
3 years ago
Read 2 more answers
At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean
GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean.  Draw a normal curve and mark these speeds.  115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145.  This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area:  normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573.  In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

8 0
2 years ago
Seventh grade
victus00 [196]

Answer:

Maybe it could be six or 30

Step-by-step explanation:

7 0
3 years ago
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