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agasfer [191]
3 years ago
10

A type of bear can run at a rate of 21 miles per hour. At this rate, how far could it run in 3 hours?​

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
8 0

Answer:63 miles

Step-by-step explanation: because 21 miles per hour is the speed and how much distance they cover so 3*21 is 63 miles

zavuch27 [327]3 years ago
6 0

Answer:

63 miles

Step-by-step explanation:

We know that the bear can run at 21 mi/hr. So, multiply 21*3 to get how many miles the bear could run in 3 hrs.

Hope it helped.

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The polynomial y = x2 - 5x + 4 has a repeated factor. (It may help to graph the equation.)
joja [24]
SOLUTION:

y = x^2 - 5x + 4

y = x^2 - 4x - x + 4

y = x ( x - 4 ) - ( x - 4 )

y = ( x - 4 ) ( x - 1 )

ANSWER:

Therefore, the answer is:

A. True.

Hope this helps! :)
Have a lovely day! <3
5 0
3 years ago
5)Write an algebraic equation for each statement, and then SOLVE for x
Andrei [34K]

Answer:

Step-by-step explanation:

1. x+6=14

  14-6=8

  x=8

2. 15/x=3

   15/3=x

   x=5

3. 7*x=56

   56/7=8

   x=8

4. x^2-4=12

  x=4, x=-4

5. 1/4x=10

  x/4 = 10

  x = 40

6. 3x-9=18

    x=9

7. 1/2x-10=14

   x/2-10=14

   x=48

8.x/8=9

   8*9=72

  x=72

9.2x+3=24

   2x=21

 x=21/2

10.20*x=140

   140/20=7

   x=7

8 0
3 years ago
Someone please help.
likoan [24]

Answer:

3a. 84

3b. 150

Step-by-step explanation:

(3*7)+(3*21)

what is 3*7? it's 21

what is 3*21? it's 63

so 21 + 63 is the answer to the first question :D

10*(8+7)

8+7 first cause it's in parentheses

15

10*15 is equal to 150

8 0
2 years ago
Can someone answer 8, 9, and 10 please?
schepotkina [342]
8)
<1 = 90
answer is a. 90

9)
k = 180 - 23 - 77
k = 80
answer is c.80
10)
x = 180 - 60 - 42
x = 78

z = 180 - 78
z = 102

y = 180 - 11 - 102
y = 67

answer is c x = 78 y = 67  z = 102

5 0
3 years ago
Samira buys a car the car loses 23% of its value in the first year. at the end of the first year her car is worth 6575.80 dollar
Andreyy89

Answer: Samira paid $8540 for her car.

Step-by-step explanation:

Let x = Amount paid by Samira for her car.

Given: Depreciation rate = 23%

Worth of car after one year = $ 6575.80

As per given,

x - 23 % of x = 6575.80

⇒ x - 0.23x = 6575.80

⇒ 0.77x= 6575.80

⇒ x= $8540   [Divide both sides by 0.77]

Hence, Samira paid $8540 for her car.

6 0
3 years ago
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