Question

Solve for x in the equation x2-8x+41=0

Answer 1

Use the quadratic formula:-

x = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2  

x =  ( 8 + sqrt (-100) / 2  and  (8 - sqrt(-100) / 2

 =  4 + 5i , 4 - 5i     Answer

Answer 2

Answer:

$x=4{\pm}5i$

Step-by-step explanation:

The given equation is:

$x^2-8x+41=0$

Since, the above equation cannot be easily factorized, thus using the discriminant method, we have

$x=\frac{-b{\pm}\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2}$

$x=\frac{8{\pm}\sqrt{64-164}}{2}$

$x=\frac{8\pm\sqrt{-100}}{2}$

$x=\frac{8\pm10i}{2}$

$x=4{\pm}5i$

Thus, the values of x are: $4+5i and 4-5i$.