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Lunna [17]
3 years ago
6

Solve for x in the equation x2-8x+41=0

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
7 0
Use the quadratic formula:-

x = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2  

x =  ( 8 + sqrt (-100) / 2  and  (8 - sqrt(-100) / 2

 =  4 + 5i , 4 - 5i     Answer
professor190 [17]3 years ago
6 0

Answer:

x=4{\pm}5i

Step-by-step explanation:

The given equation is:

x^2-8x+41=0

Since, the above equation cannot be easily factorized, thus using the discriminant method, we have

x=\frac{-b{\pm}\sqrt{b^2-4ac}}{2a}

x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2}

x=\frac{8{\pm}\sqrt{64-164}}{2}

x=\frac{8\pm\sqrt{-100}}{2}

x=\frac{8\pm10i}{2}

x=4{\pm}5i

Thus, the values of x are: 4+5i and 4-5i.

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