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Fudgin [204]
3 years ago
10

There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45

homes. Each year, 3 new homes are built in Neighborhood B.
Part A: Write functions to represent the number of homes in Neighborhood A and Neighborhood B throughout the years. (4 points)
Part B: How many homes does Neighborhood A have after 5 years? How many does Neighborhood B have after the same number of years? (2 points)
Part C: After approximately how many years is the number of homes in Neighborhood A and Neighborhood B the same? Justify your answer mathematically. (4 points)
Mathematics
1 answer:
4vir4ik [10]3 years ago
3 0
I'm only going to complete Part B. The other two are a bit easier and I believe you can do it! :D
Neighborhood A
----------------------------
Year 1: 30 increased by 20% = 6 more homes.
Year 2: 36 increased by 20% = 7.2 more homes ... 7 more homes. You cannot round in these types of problems.
Year 3: 43 increased by 20% = 8.6 ... 8 more homes.
Year 4: 51 increased by 20% = 10.2 ... 10 more homes.
Year 5: 61 increased by 20% = 12.2 ... 12 more homes.
At the end of 5 years Neighborhood A will have 73 homes in total.

Neighborhood B
---------------------------
Year 1: 45 +3 = 48
Year 2: 48 +3 = 51
Year 3: 51 +3 = 54
Year 4: 54 +3 = 57
Year 5: 57 +3= 60 homes
After 5 years Neighborhood B will have 60 homes.
Hope this helped! I will do Part A or Part C later if I have time and you still need assistance. 
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<h3>Answer: Graph a straight line through (0,-4) and (1,-8)</h3><h3>See diagram below</h3>

============================================================

Explanation:

Pick any number you want for x. I find x = 0 to be easiest. Plug this into the equation to get...

y = -4x-4

y = -4(0) - 4

y = 0-4

y = -4

This is the y intercept. The graph crosses the y axis at -4. So one point on this line is (0,-4) since x = 0 and y = -4 pair up together

---------------

Repeat for another x value, say x = 1

y = -4x-4

y = -4(1)-4

y = -4-4

y = -8

We have x = 1 and y = -8 pair up now. Therefore another point on this line is (1,-8)

We could repeat for other x values, but we have enough info to graph this straight line. We only need two points minimum to graph a straight line.

So from here all you need to do is plot (0,-4) and (1,-8). Then draw a straight line through the two points. The line extends infinitely out in both directions.

You could use any other two points you wanted. For me I just find it easiest to work with 0 and anything close to it.

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Note how starting at (0,-4) we have moved 4 units down and 1 unit to the right to arrive at (1,-8). The "4 units down, 1 unit to the right" comes exactly from the slope of -4 = -4/1

slope = rise/run = -4/1

rise = -4 means we move down 4

run = 1 means we move 1 to the right

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