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3 years ago

6

Zachary created a garden that measured7 x 6.5 feet. How many 8-foot rolls of fencing will he need to completely surround the gar

den?

1 answer:

lutik1710 [3]3 years ago

8 0

Answer:

6 rolls

Step-by-step explanation:

7 × 6.5 is 45.5

45.5 ÷ 8 is 5.6875

5.6875≈6

So 6!

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Help 5y^5/y^3 a) 5y^2 b) 5/y^2 c) 5y^8 d) 5y

WARRIOR [948]

Answer:

a) 5y²

Step-by-step explanation:

5 divided by 1 is still 5

y^5/y^3 subtract the exponents since the base is the same

6 0

3 years ago

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If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc

grin007 [14]

$(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112$

3 0

3 years ago

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

∴ [ $x^{2}$ + 3x + $\frac{12}{4}$ ] =0

∴ [ $x^{2}$ + 3x + 3 ] =0

Thus, Answer is option C : <em>[ $x^{2}$ + 3x + 3 ] =0 </em>

6 0

4 years ago

Help me please thank you

Andrews [41]

1st is parallel

2nd is perpendicular

3rd is perpendicular

4th is perpendicular

8 0

3 years ago

Simplify the algebraic expression: x(x + 3) + x(2x - 4) + 6

marusya05 [52]

Step-by-step explanation:

$x(x + 3) + x(2x - 4) + 6$

First, let's distribute the $x$ variable to each term in the first parenthesis:

$x^{2} + 3x + x(2x - 4) + 6$

Next, let's distribute the $x$ variable to each term in the second parenthesis:

$x^{2} + 3x + 2x^{2} - 4x + 6$

Next, let's group like terms together:

$(x^{2} + 2x^{2}) + (3x - 4x) + (6)$

Finally, let's add or subtract like terms to get the result:

$3x^{2} - x + 6$

6 0

4 years ago

Read 2 more answers