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3 years ago

Which of the following numbers are less than or equal to 1.75?

Mathematics

1 answer:

Dmitrij [34]3 years ago

4 0

The answer is a b and c

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(20 POINTS AND BRAINLIEST ANSWER!!!) I need help with these two geometry 1 questions!!!

Svet_ta [14]

The Second page answer is C and the first page is m/c = c/m

7 0

3 years ago

How to evaluate question number 4

ANTONII [103]

There are 2 ways that spring to mind.

One is to use the definition of the derivative at a point:

$f'(c)=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}$

In this case, $c=0$ and $f(x)=\sqrt{5-x}$ . Then

$f'(x)=-\dfrac1{2\sqrt{5-x}}\implies f'(0)=\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\dfrac1{2\sqrt5}$

- - -

If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get

$\dfrac{\sqrt{5-x}-\sqrt5}x\cdot\dfrac{\sqrt{5-x}+\sqrt5}{\sqrt{5-x}+\sqrt5}=\dfrac{\left(\sqrt{5-x}\right)^2-\left(\sqrt5\right)^2}{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac x{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac1{\sqrt{5-x}+\sqrt5}$

This is continuous at $x=0$ , so the limit is the value of the expression at $x=0$ :

$\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\lim_{x\to0}\frac1{\sqrt{5-x}+\sqrt5}=-\frac1{2\sqrt5}$

5 0

3 years ago

What is a function in algebra

Alborosie

Answer:

function is a relation between sets that associates to every element of a first set exactly one element of the second set.

.....

5 0

3 years ago

What is the equation of this line in slope-intercept form?

lara [203]

(1,-3) and(-1,5)
slope = (5 + 3)/(-1 - 1) = 8/-2 = -4
b = 1
equation
y = -4x +1

answer
<span>C.y=-4x+1</span>

3 0

3 years ago

Read 2 more answers

Hollys garden is divided into 5 equal sections. She will fence the garden into 3 areas by grouping some equal sections together.

nignag [31]

I think it will be 2 part of the garden and 3 parts left I really don't know sorry

5 0

3 years ago