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maksim [4K]
3 years ago
9

9 mugs for $45 What is the rate? And what is the unit rate?

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0

Answer:  The unit rate is $5 per  mug.

Step-by-step explanation:

To find the the unit rate, you will find the amount  one mug will cost.

If there are 9 mugs  then to get it to one, you will have to divide 9 by 9, and the same way you will have to divide 45 by 9.

45 / 9 = 5  

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What is 15% of 419.00
sasho [114]

Answer:

62.85

Step-by-step explanation:

divide bro

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3 years ago
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A rectangle has an area of (x2 - 17x + 72) square units. Since the area of a rectangle is determined using the formula, A =
Allushta [10]

Answer:

Step-by-step explanation:

x² - 17x + 72 = 0

Sum = -17

Product  = 72

Factor = 8 , 9

x² - 17x + 72 = 0

x² - 8x -9x + (-8)*(-9) = 0

x(x - 8) -9(x -8) = 0

(x - 8 ) (x - 9) = 0

Length = (x - 8) units

Width = (x - 9) units

4 0
3 years ago
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Doug is a zookeeper in charge of monitoring the "aquatic" section at the North End Zoo. A baby dolphin was born on Wednesday and
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Answer:

w(x)=2.3x+31

Step-by-step explanation:

From the information given, the function would indicate that the weight of the dolphin after x days would be equal to the 31 pounds the baby weighed when it was born plus 2.3 lbs that is the average rate it is growing for the number of days:

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w(x)= weight of the dolphin

x=number of days

7 0
3 years ago
Hi need help for this maths question
Sauron [17]

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}

c) The mean is given by the integral,

\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy

Integrate by parts, with

u = y \implies du = dy

dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}

Then

\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)

\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy

\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}

8 0
2 years ago
How to find the slope intercept equation
vladimir2022 [97]

Answer:

Solve for y to find slope intercept form

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