Answer:
0.02 or 2% = Beta
Step-by-step explanation:
Given that,
Risk-free rate = 7 percent
Expected return on the market = 10 percent
Expected return on Security J = 13 percent
Therefore, the beta of Security J is calculated as follows;
Expected return on Security J = Risk-free rate + Beta (Expected return on the market - Risk-free rate)
13 percent = 7 percent + Beta (10 percent - 7 percent)
0.13 - 0.07 = 0.03 Beta
0.06 = 0.03 Beta
0.06 ÷ 0.03 = Beta
0.02 or 2% = Beta
Answer:
m∠M = 79°
m∠N = 66°
Step-by-step explanation:
∠MPN is supplementary to ∠MPQ, so m∠MPN = 35
The sum of the measures of a triangle is 180.
So, m∠M + m∠N + m∠MPN = 180
5y + 4 + 4y + 6 + 35 = 180
9y + 45 = 180
9y = 135
y = 15
m∠M = 5y + 4 = 5(15) + 4 = 75 + 4 = 79
m∠N = 4y + 6 = 4(15) + 6 = 66
Another way to do this problem, which is easier, is to know that an exterior angle of a triangle is equal to the sum of the two remote interior angles.
That means 5y + 4 + 4y + 6 = 145
9y + 10 = 145
9y = 135
y = 15
From knowing the value of y you can now find the measures of angles M and N
Answer:
185
Step-by-step explanation:
Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg
Answer:
Ted will need 
cups of pretzels to make 15 cups of trail mix.
Step-by-step explanation:
Ted is making trail mix for a party. He mixes 1 1/2 cups of nuts, 1/4 cup of raisins, and 1/4 cup of pretzels.
So, 1/4 cup of pretzels to make 1 trail mix
x cups of pretzels to make 15 trail mix
Using the ratio and proportional
∴ x = (1/4) * 15 = 3.75 = cups.
<u>Ted will need </u><u> cups of pretzels to make 15 cups of trail mix.</u>
