Answer:
x³ + 2x² -3x +6
Step-by-step explanation:
We need to find the polynomial whose roots are ,
Say of we have zeroes as , α , β and γ , then the polynomial is ,
=> p(x) = k[ (x - α ) ( x - β) ( x - γ) ]
- where k is constant. Substituting the respective values , we have ,
=> p(x) = k [ ( x - (-2)) ( x - √3) ( x -√3)]
=> p(x) = k[ (x+2)(x² - 3)]
=> p(x) = k[ x(x² - 3) + 2(x² - 3) ]
=> p(x) = k[ x³ - 3x + 2x² - 6 ]
=> p(x) = k[ x³ + 2x² - 3x - 6 ]
<h3>
<u>Hence </u><u>the</u><u> </u><u>cubic </u><u>polynomial</u><u> is</u><u> </u><u>x³</u><u> </u><u>+</u><u> </u><u>2</u><u>x</u><u>²</u><u> </u><u>-</u><u> </u><u>3x</u><u> </u><u>+</u><u> </u><u>6</u><u> </u><u>.</u></h3>
Answer:
A Complex Number is a combination of a
Real Number and an Imaginary Number
and
Imaginary numbers, also called complex numbers, are used in real-life applications, such as electricity, as well as quadratic equations. In quadratic planes, imaginary numbers show up in equations that don’t touch the x axis. Imaginary numbers become particularly useful in advanced calculus.
Answer:
-2
Step-by-step explanation:
replace x with -4 in the h(x) function
h(x) = -2x-10 ➡ h(-4) = (-2)×(-4)-10 ➡8-10 = -2
Answer:
(x, y) = (1/2, -1)
Step-by-step explanation:
Subtracting twice the first equation from the second gives ...
(2/x +1/y) -2(1/x -5/y) = (3) -2(7)
11/y = -11 . . . . simplify
y = -1 . . . . . . . multiply by y/-11
Using the second equation, we can find x:
2/x +1/-1 = 3
2/x = 4 . . . . . . . add 1
x = 1/2 . . . . . . . multiply by x/4
The solution is (x, y) = (1/2, -1).
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<em>Additional comment</em>
If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.
A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).
