find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length
To find the perimeter of a triangle we add all the sides of the triangle
The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches
Perimeter of a triangle =
15 inches + 15 inches + 21 inches = 51 inches
So 51 inches is the perimeter
The length of the leg is 5
solution:
we know that ,
u.v = ΙuΙ ΙvΙcosθ
here,
θ =60° (since the given triangle is equilateral triangle)
u.v = ΙuΙ ΙvΙcos60°
= 1 x 1 x 1/2
u.v = 1/2
now, u.w = ΙuΙ ΙwΙcosθ
= ΙuΙ x cos(60x2)
u.w = -1/2
The answers to the questions
Answer:
A
Step-by-step explanation:
Cosine is the ratio of "adjacent" to "hypotenuse"
With respect to the Angle E, the adjacent side is FE and the hypotenuse (always opposite side to 90 degree angle) is DE.
We are given DE = 26, but we need FE. We will solve for FE using Pythagorean Theorem, which tells us:
leg^2 + another leg^2 = hypotenuse^2
So, we will have:
10^2 + FE^2 = 26^2
Now, we solve for FE:

So,
Cos(E) = adj/hyp = 24/26
Correct answer is A