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iren2701 [21]
3 years ago
7

If the equation y=6x+20 represents the line on the graph, determine how much Skyler will have in her savings after 18 months. he

lppppp!!!!
Mathematics
1 answer:
NikAS [45]3 years ago
3 0
Skyler would have $128.

Multiply 18 by 6 and then add 20.
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12.6% of<br>RI 149 390bn​
galina1969 [7]

Answer: RI 18,823.14

Step-by-step explanation:

I guess that we want to find the 12.6% of Rl 149,390

First, we assume that Rl 149,390 is the 100%

Then we can write an equation like:

Rl 149,390 = 100%

Then if the amount X is the 12.6%, we also have the equation:

X = 12.6%

Then we have the two equations:

X = 12.6%

Rl 149,390 = 100%

If we take the quotient between these two equations we get:

(X/Rl 149,390) = (12.6%/100%)

Solving this for X we get:

X =  (12.6%/100%)*(Rl 149,390) = RI 18,823.14

7 0
2 years ago
Interval Notation <br> Inequality Notation <br> Pls help
Andrew [12]

Step-by-step explanation:

Interval notation

[ 10, +\infty \rang

Inequality Notation

x \geq 10

4 0
2 years ago
Help please!!!! will upvote answers!!!!
statuscvo [17]
Formula for finding the area of a rectangle: length x width

Formula for finding the volume of a rectangular prism: V = lwh
7 0
3 years ago
Ezra measured a swimming pool and made a scale drawing. He used the scale 9 millimeters = 1 meter. What is the scale factor of t
mr Goodwill [35]
1mm = .11m

You can get this by simplifying the numbers you already have
6 0
3 years ago
Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)
PtichkaEL [24]

Answer:

(x^{-3} )^{2}

x^6 x^{-12}

Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}

Both the formula can be applied to the expression((x^{3} x^{-6} )^{2}) during the first step while solving it.

<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}

So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

8 0
2 years ago
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