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allsm [11]
3 years ago
14

HELP PLEASE ! find the area of the shape below

Mathematics
2 answers:
White raven [17]3 years ago
8 0

Answer:

area = 202.5 yd²

Step-by-step explanation:

area = (15 x 12 ) + (3)(15)(0.5)

area = 180 + 22.5 = 202.5 yd²

Brums [2.3K]3 years ago
6 0

Answer: 36

Step-by-step explanation:

  • A=Hxw- Height  x width
  • so the Height is 12 and the width is 3
  • You multiply 12x3
  • =36
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Please help! <br> Use the Law of Cosines to find the values of x and y.
Romashka [77]

Answer:

x = 8.39

y = 55.2

Step-by-step explanation:

9² + 1² - 2(9)(1)cos(50) = x²

x = 8.39

9/sin(y) = x/sin(50)

sin(y) = 0.8215200692

y = 55.23724927

8 0
3 years ago
Given g(x) = x2-8x-20, which statement is true?
sveticcg [70]

Answer:C

Step-by-step explanation:

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2 years ago
NO LINKS!! Please help me with these graphs. Part 1​
AveGali [126]

Problem 9

The instructions aren't stated anywhere, but I'm assuming your teacher wants you to find the equation of each parabola.

The vertex here is (h,k) = (-6,-4) which you have correctly determined.

This means

y = a(x-h)^2 + k\\\\y = a(x-(-6))^2 +(-4)\\\\y = a(x+6)^2 - 4\\\\

Next we plug in one of the other points on the parabola. We cannot pick the vertex again. Let's pick the point (-4,0) which is one of the x intercepts. We'll do this to solve for 'a'

y = a(x+6)^2 - 4\\\\0 = a(-4+6)^2 - 4\\\\0 = a(2)^2 - 4\\\\0 = a(4) - 4\\\\0 = 4a-4\\\\4a-4 = 0\\\\4a = 4\\\\a = 4/4\\\\a = 1\\\\

This means

y = a(x+6)^2 - 4\\\\y = 1(x+6)^2 - 4\\\\y = (x+6)^2 - 4\\\\

represents the equation of the parabola in vertex form.

<h3>Answer: y = (x+6)^2 - 4\\\\</h3>

========================================================

Problem 10

The vertex is (h,k) = (-2,-6)

So,

y = a(x-h)^2 + k\\\\y = a(x-(-2))^2 + (-6)\\\\y = a(x+2)^2 - 6\\\\

Now plug in another point on the parabola like (-1,-8) and solve for 'a'

y = a(x+2)^2 - 6\\\\-8 = a(-1+2)^2 - 6\\\\-8 = a(1)^2 - 6\\\\-8 = a(1) - 6\\\\a-6 = -8\\\\a = -8+6\\\\a = -2\\\\

<h3>Answer:  y = -2(x+2)^2 - 6\\\\</h3>

For each equation, you could optionally expand things out to get it into y = ax^2+bx+c form, but I think it's fine to leave it as vertex form.

7 0
1 year ago
Read 2 more answers
Which line is represented by the function f(x)=2x+1
solong [7]
That's linear function so it's a straight line if that's what you mean
4 0
3 years ago
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write the equation of the line with slope 3 that passes through the point (-1,6) in slope-intercept form
GalinKa [24]

Answer:

y=3x+9

Step-by-step explanation:

By knowing the slope of the line, and one point it has to go through, we can easily write the equation of the line by starting with the general form of a line in "point-slope" form. That is a line of slope "m" and going through the point (x_0,y_0) on the plane, can be written in its "point-slope" form as:

y-y_0=m(x-x_0) and subsequently solving for "y" in the equation to get it in its "slope-intercept" form.

Therefore, in our case, with slope (m) equal to 3, and the point (x_0,y_0) equal to (-1, 6), we get:

y-y_0=m\,(x-x_0)\\y-6=3\,(x-(-1))\\y-6=3\,(x+1)\\y-6=3x+3\\y=3x+3+6\\y=3x+9

5 0
2 years ago
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