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larisa [96]
3 years ago
9

I NEED HELP PLEASE!!!

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer: Part a) translate g(x) 6 units to the right, Translate f(x) 6 units to the left

Part b) k=3 (slope)

Step-by-step explanation:

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The dimensions of a 4−cm by the 4−cm rectangle are multiplied by 1/2 (as a fraction). How is the area of the rectangle affected?
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Answer:

1/2 is just saying 0.5

Step-by-step explanation:

half of one is 0.5 or 1/2

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Is this right ? Im honestly confused
fgiga [73]

Answer:

In step by step

Step-by-step explanation:

For #1, everything is perfect.

For #2, you wrote your functions out incorrectly, but your x input and y output are correct

#3 is a little messed up.

Your function is f(x)=-3x+1. Your given x's are -3, -1, 0, 1, 2, and 3. Plug all of these in.

1. f(-3)=-3(-3)+1

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2. f(-1)=-3(-1)+1

  • f(-1)=3+1
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3. f(0)=-3(0)+1

  • f(0)=0+1
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4. f(1)=-3(1)+1

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5. f(2)=-3(2)+1

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3 years ago
If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e
Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

  • <em>99 is an outlier of pet group</em>
  • <em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

n = 15

The quartiles positions are:

Q_1 = \frac{n + 1}{4}

Q_1 = \frac{15 + 1}{4}

Q_1 = \frac{16}{4}

Q_1 = 4th

Q_3 = Q_1 \times 3

Q_3 = 4th \times 3

Q_3 = 12th

So, we have:

Q_1 = 4th

Q_3 = 12th

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

Q_1 = 68

Q_3= 79

The lower and upper limits of the outlier are:

L = Q_1 - 1.5 \times (Q_3 - Q_1)

U = Q_3 + 1.5 \times (Q_3 - Q_1)

So, we have:

L = 68 - 1.5 \times (79 - 68)

L = 51.5

U = 79+ 1.5 \times (79 - 68)

U = 95.5

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

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IgorC [24]

Answer:

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15% = 0.15
15% of 71.85 is equal 0.15*71.85 ≈ 10.78
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