If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18.
<h3>What is an ideal gas equation?</h3>
The ideal gas equation is given below.

The equation can be written as

Where M is the molar mass, P is the pressure, V is the volume, R is the universal gas constant, T is the temperature, and m is the mass of the gas.
Then the molar mass of a 0.622-gram sample of gas has a volume of 2.4 L at 287 K and 0.850 atm.
V = 2.4 L = 0.0024
P = 0.85 atm = 86126.25 Pa
T = 287 K
m = 0.622
R = 8.314
Then we have

Then the molar mass of the gas is 7.18.
More about the ideal gas equation link is given below.
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the answer is c...........
Answer: 5/6
Step-by-step explanation: If you graph out the relation and you do rise/run. You get 5 for the rise and 6 for the run.
Hope this helps! Please mark me brainiest.
Answer:
where is the shapes?
Step-by-step explanation:
gimmie the shapes and I'll answer
Answer:
67.6275
Step-by-step explanation:
ok so 88.5-25=63.50
63.50*6.50%=4.1275
63.50+4.1275=67.6275