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ICE Princess25 [194]
3 years ago
9

Can someone help me with this writing assignment?

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Take from this what you can

Step-by-step explanation:

A rational function as any function which can be defined by a rational fraction I in algebraic fractions such that both the numerator and the denominator are polynomials

Functions as a form of the non rational function which is usually defined as a function that can be written as the quotient of 2 polynomials with integral coefficients

This is a rational function

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Help me plss need help with theses three
fiasKO [112]
interior angle of a regular 18-gon.
It is easier to calculate the exterior angle of a regular polygon of n-sides (n-gon) by the relation
exterior angle = 360/n
For a 18-gon, n=18, so exterior angle = 360/18=20 °
The value of each interior angle is therefore the supplement, or
Interior angle = 180-20=160 degrees.

Naming of a 9-gon
A polygon with 9 vertices is called a nonagon (in English) or enneagon (French ennéagone, but the English version is sometimes used)
You had a good start with the correct answer.

Exterior angle of a 15-gon
The exterior angle of a 15-gon can be calculated using the relation given in the first paragraph, namely
Exterior angle = 360/15=24 degrees
4 0
3 years ago
Which product is positive?<br> ( 13 ( 31 )<br> ( 31 )<br> (3) ( 13 (1)
Anastaziya [24]
The first one because it’s (13(31)
8 0
3 years ago
Q # 13. please help to solve this
True [87]
To solve this problem you must apply the fomrula for calculate the area of a cylinder, which is shown below:
 A=2πrh+2πr^2
 Where r is the radius and h is the height of the cylinder
 You have that r=15.1 inches and h=12.8 inches, then:
 A=2πrh+2r^2
 A=2π(15.1 in)(12.8 in)+2π(15.1 in)^2 
 A=2647 in^2
 The answer is 2647 in^2
3 0
3 years ago
What is the area of the rectangle shown?
photoshop1234 [79]

As a fraction:

11/36

As a Decimal:

0.30555555

4 0
3 years ago
Read 2 more answers
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
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