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arsen [322]
3 years ago
8

F(x) = -x^2+10x - 17

Mathematics
1 answer:
Viktor [21]3 years ago
8 0

Answer:

theres a graph with the vertex values if that's what you were looking for

Step-by-step explanation:

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15PTS PLEASE HELP ASAP!<br> (dont write random answers pls!)
Tcecarenko [31]

Answer:

52

Step-by-step explanation:

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4 0
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The Perfect square numbers between 100 and 200 are ____<br> Pls help.
svetlana [45]

Step-by-step explanation:

The perfect square numbers between 100 and 200 are :

10^2 =100

11^2 =121

12^2 =144

13^2 =169

14^2 =196

4 0
3 years ago
Solve [(x+7) x 3-5] / 4 = 7<br> What is the first step in this equation
Nitella [24]

Answer:

The first step is to slove the numbers in the brackets

Step-by-step explanation:

[(x+7) x -2] / 4 = 7

-2(x+7) / 4 = 7

-2x-14 / 4 = 7

-2x-14 = 28

-2x = 42

x = -21

PEMDAS

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3 years ago
Consider the absolute value function f(x)=-|x+2|-2 The vertex of the function is
Black_prince [1.1K]
(-2,-2)


Since it has a negative in front of the absolute value, the graph is a downward cone.
3 0
3 years ago
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M is the midpoint of AN, A has coordinates
maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

8 0
3 years ago
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